cucumber

nevar saprat ko tu isti vielies? katru reizni nerakstit <table><tr> .... (ja shito tad JS vai PHP) vai uzlikt stilu uz tabulu? table, tr, td { tavs css }

Kaut kas dabut shita, ja atstarpju vairak par 3 nebus. var longstring = "9 http://supermens.lv/upload/thumbs/e85016e22b68b05155e601ae80cc02bd.png Kaut kas"; var brokenstring = longstring.split(" "); var totChars = 0; for ( i = 0; i < 3; i++) { totChars += brokenstring[i].length; } alert(longstring.substring(totChars-2));

Sorry, my false. Sadalu nosaukumi baigi nepamanami. Ideja tak nemainas. var longstring = "Most of the time Amrit is confused — OK, not most of the time"; var brokenstring = longstring.split(" ",3); brokenstings, dalisies aiz komatiem

Ka ta $string = '9 http://supermens.lv/upload/thumbs/e85016e22b68b05155e601ae80cc02bd.png Kaut kas'; list($id,$url,$com) = explode(' ', $string, 3); Citāts nebija vajadzīgs

Man kaut ka neliekas korekti, pienemsim ka max ir skaitlis ir 3, tad 3+4 = 7 / 5 = 1,4 * 5 = 7 //bezjega sanak dalit un tad atpakal reizinat?

Sanak mazak lietot, f-jas un dalishanu, strada aptuveni tapatas. $data = array(11,2,3,6,12,7,3,43,12); $max = max($data); while ($max % 5 != 0 ) { $max++; } $step = $max / 5; foreach($data as $value) { if ($value >= $step * 0 && $value <= $step * 1 ) { $result[1][] = $value; continue;} if ($value >= $step * 1 && $value <= $step * 2 ) { $result[2][] = $value; continue;} if ($value >= $step * 2 && $value <= $step * 3 ) { $result[3][] = $value; continue;} if ($value >= $step * 3 && $value <= $step * 4 ) { $result[4][] = $value; continue;} if ($value >= $step * 4 && $value <= $step * 5 ) { $result[5][] = $value; continue;} } print_r($result);

Jap patesteju ari uz saviem piemeriem, it ka strada ok. Paldies. Radas vel viena ideja, pameginashu rit realizet.

Jap laacz, tev bus taisniba

1. grupa 2,3,3 2. grupa 6,7,11,12 3.grupa - 4. grupa - 5. grupa 43 Tads vel piemers. Ja butu skaitli 1,2,3,4,5, tad grupas butu 1.gr - 1 , 2.gr - 2 .. 5.gr - 5 Es to iedomajos, ka skaitlu virkni augosha seciba, kas ir sadalita piecas dala ar vienotu vertibu intervalu.

Ideja ir tada, ka var but ari tuksha ta grupa, vinai pilnai nav jabut vienmer.

Tava piemera bik kludas. Sanak atpakal es dabuju 5 grupas, bet katra ir pa vienam elemetam, bet vajadzetu visus elemtus sadalit pa attiecigam grupam. //izlabotas $cik_grupa = 5; $numbers = array(11,2,3,6,12,7,3,43,12); sort($numbers); $cik_grupas_sanak = floor(sizeof($numbers)/$cik_grupa); $grupas = array(); for($x=0;$x<$cik_grupas_sanak;$x++){ $grupas[] = array_slice($numbers,$x * $cik_grupa,$cik_grupa); } print_r($grupas);

Isti pareizi nevaru izdomat, ka var sadalit skaitlus grupas (intervalos), pienemsim pa 5. Sanak ka skaitli tiek iedaliti piecas grupas, ja skaitlu pietrukst, lai sadalitu grupa, tad shi grupa ar skaitliem paliek tuksha. Grupa 5 ir skaitli vislielako skaitli utt, kamer grupa 1 ir mazaki skaitli no kopejiem skaitliem. //TEST 1 $numbers = array(11,2,3,6,12,7,3,43,12); $min = min($numbers); $max = max($numbers); $div = ceil(($min+$max+1)/5); foreach ($numbers as $number) echo ceil(($number)/$div)."\n"; //2 1 1 1 2 1 1 5 2 //TEST 2 $numbers = array(11,2); $min = min($numbers); $max = max($numbers); $div = ceil(($min+$max+1)/5); foreach ($numbers as $number) echo ceil(($number)/$div)."\n"; //4 1 te it ka vajadzetu but 5 un 1 //TEST 3 //kaut kas uz to pusi bet ari nav tas $numbers = array(11,2,3,6,12,7,3,43,12); sort($numbers); print_r(array_chunk($numbers, 5));

Sakum lapa nepark patik, ka viss galvenais kontents ir nobidits kreisaja puse. Edit. Nevar ielades savu foto, visi vecie avatari pazudushi

Iz katas kadi brinumi ar mainigajiem, tapec ari nosuti kadu kreiso headeri gala. $subject ="$subject"; $message="$detail"; $mail_from="$customer_mail"; $header="From: <$mail_from>";

Vel varetu but tads risinajums, turet visus ads bannerus main root'a un ik pec laika mainit viniem nosaukums. Tad vismaz vienu reizi lietotajs ieraudzis to banneri. Protams direktorijas roots butu nesmuks.

ta jau mapites DB neveido izmanto kadu tuli vai raksti mysql.exe faila CREATE TABLE fusion;

kaut ka neticas. paradi kodu? ja piespiedu karta vajag sesiju nonemt izmanto f-ju sission_destroy();

Lieto kadu php zip clasi, foruma aprunats

Tad izmanto mysql lauka unix_timestamp

document.getElementById('count').value getbyID kuku ID var but tikai viens un tas pats nav atrodams

Es tak skaidri un gaishi pateicu kur ir errors SQL'a, ta ka tu uzrakstiji nestradas un vis Otrs, izmanto php.lv/paste shitik lieliem koda blokiem Treshkart, tev nemaz uz sql'u id salidzinashanas vertiba nenonak JS ar apskaties velreizs

Beidz pikstet she paginatoru lieto uz nebedu

ob_start(); // pirmaja rinda aiz <?php risinajums 4z, bet stradas uz goda ps. foruma 100% bija andrisp aprakstijis siki un smalki sho lietu, searchot ar kadreizs vajag

<select id="Hell_iboi" name="keyWords[]" size="5" multiple="multiple"> // paradas masivs [] un id lidz galam

Nu tak lasi ko tev raksta SELECT * FROM 'navigacija' WHERE 'id' = '".$q."'"; jabut $q = mysql_escape_stirng($q); SELECT * FROM `navigacija` WHERE `id` = '".$q."'"; /* savadakas pedinas */