nekas nemainās.. tas pats error. :(
bet vai tas ko manītu, ja piebilstu , ka poga darbojās ar ajax?
- pogas kods -
<div class="main">
<div id="list">
<img src="sakums.png" alt="sākums" value="1" onclick="showUser(this.value)"/><br>
<img src="darbi.png" alt="mani darbi" value="2" onclick="showUser(this.value)"/><br>
<img src="kontakti.png" alt="kontakti" value="3" onclick="showUser(this.value)"/><br>
</div>
<div id="show">
<!-- te nāk ajax sarazotie dati. -->
</div>
</div>
- ajax kods -
var xmlHttp;
function showUser(str)
{
xmlHttp=GetXmlHttpObject();
if (xmlHttp==null)
{
alert ("Browser does not support HTTP Request");
return;
}
var url="get.php";
url=url+"?q="+str;
url=url+"&sid="+Math.random();
xmlHttp.onreadystatechange=stateChanged;
xmlHttp.open("GET",url,true);
xmlHttp.send(null);
}
function stateChanged()
{
if (xmlHttp.readyState==4 || xmlHttp.readyState=="complete")
{
document.getElementById("show").innerHTML=xmlHttp.responseText;
}
}
function GetXmlHttpObject()
{
var xmlHttp=null;
try
{
// Firefox, Opera 8.0+, Safari
xmlHttp=new XMLHttpRequest();
}
catch (e)
{
//Internet Explorer
try
{
xmlHttp=new ActiveXObject("Msxml2.XMLHTTP");
}
catch (e)
{
xmlHttp=new ActiveXObject("Microsoft.XMLHTTP");
}
}
return xmlHttp;
}
- nu un protams jau augstāk minētais php kods -
<?php
$q=$_GET["q"];
$con = mysql_connect('localhost', 'root', 'pass');
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("portfolio", $con);
$sql="SELECT * FROM 'navigacija' WHERE 'id' = '".$q."'";
$result = mysql_query($sql) or die(mysql_error());
echo "<table border='1'>
<tr>
<th>id</th>
<th>name</th>
<th>content</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['content'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysql_close($con);
?>