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jQuery on() funkcijas kļūda


ziedinjsh
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Sveiki! Ir tāda lieta, ka jQuery on() funkcija nostrādā tikai vienu reizi. Doma ir sekojoša uzspiežot uz trigera parādās rezūltāts, viņu var spaidīt daudz un dikti, bet tikai ne uz IE. Interesantākais, ka atverot inspect elements (ko piedāvā IE) tad strādā, līdz ko viņu aizver, nestrādā. Vai kāds zin atbildi? :D

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jQuery('#showAwr').on('click', function(){

jQuery('.form').fadeOut(200,function(){

jQuery.getJSON('process/home.php?w=getawr', function(data) {

for (var i in data) {

var id = data.aid;

var awr = data.answer;

var like = data.likes;

var dislike = data.dislikes;

var answer = '<div class="awrtext">'+awr+'</div>'+

'<div class="option">'+

'<ul id="awrotn">'+

'<li id="'+id+'" class="like btn"><span class="likec">'+like+'</span></li>'+

'<li id="'+id+'" class="dislike btn"><span class="dislikec">'+dislike+'</span></li>'+

'<div class="fix"></div>'+

'</ul>'+

'</div>';

 

jQuery('.answer').fadeIn(200).html(answer);

console.log(answer);

jQuery('.similar').hide('slide', { direction: 'right' }, 300, function(){

jQuery('.similar').html('');

});

}

});

});

return false;

});

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Nu tāāāā...

Pirmkārt jau tu ciklē cauri tam data objektam un katrā iterācijā liec HTML saturu vienā un tajā pašā elementā: "jQuery('.answer').fadeIn(200).html(answer)" - btw,šeit prasās secību otrādāk -, kā arī turpat slēp tos ".similar" elementus.

 

Bet eventu šeit nekas neatbaindo.

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uztaisīju promitīvāku.. tāpat neiet

jQuery('#showAwr').on('click', function(){
	jQuery.getJSON('process/home.php?w=getawr', function(data) {
		for (var i in data) {
				var id = data[i].aid;
				var awr = data[i].answer;
				var like = data[i].likes;
				var dislike = data[i].dislikes;
				var answer = '<div class="awrtext">'+awr+'</div>'+
				'<div class="option">'+
					'<ul id="awrotn">'+
						'<li id="'+id+'" class="like btn"><span class="likec">'+like+'</span></li>'+
						'<li id="'+id+'" class="dislike btn"><span class="dislikec">'+dislike+'</span></li>'+
						'<div class="fix"></div>'+
					'</ul>'+
				'</div>';
				jQuery('.answer').html(answer);
		}		
	});
});	
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