snach15 Posted December 30, 2012 Report Posted December 30, 2012 Sveiki, nesanāk ielikt MySql funkciju iegš javascript .. šādi neder ... kā lai to paveic? function skatits(x) { ?> mysql_query("UPDATE script"); <? } Quote
snach15 Posted December 30, 2012 Author Report Posted December 30, 2012 test.php atrodas Mysql kvērijs kurš updeito datubāzi. kā panākt lai viņš neatverot to failu test.php izpilda darbību? function skatits() { location.href='test.php'; } Quote
snach15 Posted December 30, 2012 Author Report Posted December 30, 2012 atrisināju ... <script> function skatits() { var oHead = document.getElementsByTagName('HEAD').item(0); var oScript= document.createElement("script"); oScript.type = "text/javascript"; oScript.src="test.php"; oHead.appendChild( oScript); } </script> Quote
F3llony Posted December 30, 2012 Report Posted December 30, 2012 Coder, what are You doing? Coooooooder, stahp! STAAAHHHHHHHHP! NO STAHHHHPPPPPPPPP! OH CODER!!! Quote
briedis Posted December 30, 2012 Report Posted December 30, 2012 Pameklē internetā, kas ir ajax. Quote
snach15 Posted December 30, 2012 Author Report Posted December 30, 2012 taadi komentāri :D pff nēesmu jav nekāds koders! nāku pēc padoma un palīdzības nevis stūlbiem komentāriem .. nomierinās sikie geki! Quote
mad182 Posted January 3, 2013 Report Posted January 3, 2013 Tas ko tu dari ir līdzvērtīgs skrūves dzīšanai sienā ar āmuru. Quote
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