Atvērt popup p\ec formas funkcijas

[ziedinjsh]

Saistībā ar citu jautājumu man radās šāds: Kā var atvēr popup kurā parādās pievienošanas rezūltāts?

 

<?php
$data = mysql_fetch_array(mysql_query("SELECT * FROM users WHERE user_email='".$_SESSION['user_email']."' LIMIT 1"));
$users = mysql_query("SELECT * FROM users");

if(isset($_POST['send_msg'])){

$msg_to = $_POST['msg_to'];
$msg_from = $data['user_id'];
$msg_title = mysql_real_escape_string($_POST['msg_title']);
$msg_text = mysql_real_escape_string($_POST['msg_text']);
$msg_date = date("Y-m-d H:i:s");
$msg_status = "0";

$sql = ("INSERT INTO messages (msg_to, msg_from, msg_title, msg_text, msg_date, msg_status) VALUES ('$msg_to', '$msg_from', '$msg_title', '$msg_text', '$msg_date', '$msg_status')");
$result = mysql_query($sql);

if($result){
// šeit atveras popup document.getElementById('succsess').style.display='block';document.getElementById('fade').style.display='block'
}else{
// šeit atveras popup document.getElementById('error').style.display='block';document.getElementById('fade').style.display='block'
}

}
echo "<div id='new-msg'>";
echo "<form method='post' action='".$_SERVER['PHP_SELF']."'>";
echo "<p>Kam</p><p><select name='msg_to' class='msgselect'>";
while ($data = mysql_fetch_array( $users )) {
echo "<option value='".$data['user_id']."'>".$data['user_name']."</option>";
}
echo "</select></p>";	

		echo "<p>Tēma</p> <p><input type='text' name='msg_title' class='msgtitle'></p>";
			echo "<p>Saturs</p> <p><textarea name='msg_text' class='msgtext'></textarea></p>";
				echo "<p><input type='submit' name='send_msg' value='Sūtīt vēstuli' class='msgbutton'></p>";
echo "</form>";				
echo "</div>";


openpopup("succsess");
echo "Vēstule veiksmīgi nosūtīta!";
closepopup();
openpopup("error");
echo "Vēstule nav nosūtīta...";
closepopup();
?>

 

Kā tas ir panākāms!?

Edited March 7, 2011 by ziedinjsh

[m8t]

alert();?

 

ps. - ieteikums -> mācies JQuery. Noderēs ;)

[ziedinjsh]

nu aler tas ir windows logs.. bet kā atvert šo popup ko izmantoju lapā?

 

document.getElementById('succsess').style.display='block';document.getElementById('fade').style.display='block'

[m8t]

<script type="text/javascript">
<!--
YOUR SCRIPT HERE
-->
</script>

?

[daGrevis]

Kā izskatās Tavs "pop-up"? =/

[ziedinjsh]

neiet vienalga.. vai arī es nepareizi daru kaut ko!

<?php
$data = mysql_fetch_array(mysql_query("SELECT * FROM users WHERE user_email='".$_SESSION['user_email']."' LIMIT 1"));
$users = mysql_query("SELECT * FROM users");

if(isset($_POST['send_msg'])){

$msg_to = $_POST['msg_to'];
$msg_from = $data['user_name'];
$msg_title = mysql_real_escape_string($_POST['msg_title']);
$msg_text = mysql_real_escape_string($_POST['msg_text']);
$msg_date = date("Y-m-d H:i:s");
$msg_status = "0";

$sql = ("INSERT INTO messages (msg_to, msg_from, msg_title, msg_text, msg_date, msg_status) VALUES ('$msg_to', '$msg_from', '$msg_title', '$msg_text', '$msg_date', '$msg_status')");
$result = mysql_query($sql);

if($result){
?>
<script language="javascript" type="text/javascript">
document.getElementById('succsess').style.display='block';document.getElementById('fade').style.display='block';
</script>
<?php
}else{
?>
<script language="javascript" type="text/javascript">
document.getElementById('error').style.display='block';document.getElementById('fade').style.display='block';
</script>
<?php
}

}
echo "<div id='new-msg'>";
echo "<form method='post' action='".$_SERVER['PHP_SELF']."'>";
echo "<p>Kam</p><p><select name='msg_to' class='msgselect'>";
while ($data = mysql_fetch_array( $users )) {
echo "<option value='".$data['user_name']."'>".$data['user_name']."</option>";
}
echo "</select></p>";	

		echo "<p>Tēma</p> <p><input type='text' name='msg_title' class='msgtitle'></p>";
			echo "<p>Saturs</p> <p><textarea name='msg_text' class='msgtext'></textarea></p>";
				echo "<p><input type='submit' name='send_msg' value='Sūtīt vēstuli' class='msgbutton'></p>";
echo "</form>";				
echo "</div>";


openpopup("succsess");
echo "Vēstule veiksmīgi nosūtīta!";
closepopup();
openpopup("error");
echo "Vēstule nav nosūtīta...";
closepopup();
?>

 

popup:

function openpopup($title){
echo "<div id='$title' class='wstyle'>";
echo "<div class='popup'>";
	echo "<div class='content'>";
		echo "<a href = \"javascript:void(0)\" onclick = \"document.getElementById('$title').style.display='none';document.getElementById('fade').style.display='none'\"><img class='close' src='img/close.png'></a>";
}
function closepopup(){
	echo "</div>";
echo "</div>";
echo "</div>";
}

[wintermute]

<script type="text/javascript">
<!--
YOUR SCRIPT HERE
-->
</script>

Šitā nav īsti labi.

Būtu jābāt:

 

<!-- priekš HTML5 -->
<script src="/path/tp/your.js"></script>

<!-- priekš XHTML 1.0 Strict -->
<script src="/path/tp/your.js" type="text/javascript"></script>

 

 

Un pilnīgi noteikti NE ŠITĀ

 echo "<a href = \"javascript:void(0)\" onclick = \"document.getElementById('$title').style.display='none';document.getElementById('fade').style.display='none'\">
<img class='close' src='img/close.png'></a>";

 

Ziediņš, varbūt ir pienācis laiks beidzot iemācīties javascript : http://eloquentjavascript.net/index.html

[ziedinjsh]

Tas ko noraadiiji "Un pilnīgi noteikti NE ŠITĀ " tas ir links kursh aizver popup.. tads jau vinjsh var palikt.. bet kaa tad atver popup mysql dautu ievadiishanas rezultaataa?? Ar funkciju?