andism88 Posted February 20, 2009 Report Posted February 20, 2009 (edited) Sveiki! tātad ir uztaisīts skripts : <?php if ($handle = opendir('faili')) { while (false !== ($file = readdir($handle))) { if ($file != "." && $file != "..") { echo '<a href="index.php?p=faili&f='."$file\n".'">'."$file\n".'</a><BR>'; } } closedir($handle); } ?> Kuršs darbojā pilvērtīgi, bet vajag panākt lai vinjs izvada tikai faila nosaukumu bez paplasjinājumu (piemēram "fails.doc" vietā tikai "fails".. Kāds var palīdzēt.. Paldies :) Edited February 20, 2009 by andism88 Quote
superKrona Posted February 20, 2009 Report Posted February 20, 2009 $file = substr($file, 0, -4); Quote
andism88 Posted February 20, 2009 Author Report Posted February 20, 2009 $file = substr($file, 0, -4); Paldies šis strādā un pagaidām der :) Bet kā rīkoties ja faila paplašinājumam nebūs 3 burti bet vienam failam piemēram 2 vienam 3 un vēl kādam četri (pagaidā varu iztikt ar šo, bet jamācās n;akotei :) ) Quote
x000x01 Posted February 20, 2009 Report Posted February 20, 2009 (edited) $search = '(\.)(.*)'; $replace = '\\1'; $file = ereg_replace( $search, $replace, $file ); Edited February 20, 2009 by x000x01 Quote
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