FT3

vai ir iespejams ustajsit lai

ik 1 datumu datubaze updato visus ierakstus un uzliek 0 ,

nejienakot nekada faila vai linka . tipa AUTO :D

vel ir viena problema ?!

vai nau vel lidziga koda vai scripta

($_SERVER['HTTP_REFERER']) šis man neder jo viņš ņem adreses ar :

http://ADR.lv/?go=donate

http://ADR.lv/?p=forum

http://ADR.lv/?page=news

bet man vajadzetu lai būtu (http://ADR.lv/)

Varbut ir kads scripts kurš varetu apgriezt "?go=donate" un tc.

Vai ari kautkads replace kods , piem pec /// viņš visu izdeš :)

Jap pareizi saprati plds :)

tnx sapludoju :)

Iframe ir ielikts cita majaslapa bet iekš iframe ir kods $_SERVER['HTTP_HOST'];

Vai ir iespejāms ņemt nevis iframe linku bet gan tas majaslapas kur viņš ir ielikts ?

un ka lai apvienot tgd $output = strTr( $text, $smilies ); ar echo $string; ? ?

Warning: preg_replace() [function.preg-replace]: Compilation failed: unmatched parentheses at offset 1 in C:\AppServ\www\forum\2.php on line 5

 

Warning: preg_replace() [function.preg-replace]: Compilation failed: unmatched parentheses at offset 2 in C:\AppServ\www\forum\2.php on line 6

 

Warning: preg_replace() [function.preg-replace]: Compilation failed: missing ) at offset 2 in C:\AppServ\www\forum\2.php on line 7

 

Warning: preg_replace() [function.preg-replace]: Compilation failed: missing ) at offset 3 in C:\AppServ\www\forum\2.php on line 8

 

Warning: preg_replace() [function.preg-replace]: Compilation failed: unmatched parentheses at offset 1 in C:\AppServ\www\forum\2.php on line 13

 

Warning: preg_replace() [function.preg-replace]: Compilation failed: unmatched parentheses at offset 2 in C:\AppServ\www\forum\2.php on line 14

njam visu itka sapratu bet ka tgd ar tavu

$string = preg_replace("/\[b\](.*)\[\/b\]/Usi", "<b>\\1</b>", $string);

ustajsit smaidiņus ?

EdgarsA tnx ,

kā man besī, kad iedod rokās, bet pašam grūti pat iedziļināties ..

Vnk ilgu laiku biju aiznemts ar to 1 kodu :)

$adress = $_SERVER['HTTP_HOST'];
$link = $_SERVER['PHP_SELF'];


$query = mysq_fetch_object(mysql_query("select count(id) as cnt from clients where adress='$adress'"));
if($query->cnt == 0){
mysql_query("insert into clients (adress,link) values ('$adress','$link')");
}

Fatal error: Call to undefined function mysq_fetch_object()

what ? ^_^

nejau taja zina :)

piem

table sastav no

=================

id

homepage

ip

=================

es padodu homepage=http://nosukums.lv posts viņš parbauda , ja taja homepage tabula jau ir http://nosukums.lv viņš neko nedara :)

vari isak pateikt kur jaieraksta tekstu un ar ko lai izvada ? :)

vjg parbaudes kodu

pirms ievietošanas datubaze parbauda

ja tads nosaukums(field) jau eksiste - nepievieno

ja nosaukums(field) neeksiste tad veidojas mysql insert

Cerams sapratat :)

<?php
$replace_array = array(
//BB CODES
'[bb]' => '<B>',
'[/bb]' => '</B>',
//ANTI
'<' => '<',
'>' => '>',
//SMILES
':)' => '<img src="http://www.krot.lv/engine/modules/mchat/smiles/smile-23.gif" alt=":)" />', 
':(' => '<img src="http://sartira.net/engine/modules/mchat/smiles/smile-20.gif" alt=":(" />' 
);

$text_t = str_ireplace(array_keys($replace_array), $replace_array, $text_t);
?>

kad teksts ir [bb]TEKSTS[/bb] rada <b>TEKSTS</b> bet vajag lai butu TEKSTS

es zinu del ka tas ir del < = < un > = > , bet ka lai ustajsit ka [bb] šim kodam butu izņemums ? !

Tada lieta kad uzpiezu uz attelu nekas nemainas ?!

bet ja uzlieku type "submit" viss strada, help

Kas pa vainu ?

<?php
session_start();

if($_POST['LV']){
$_SESSION['valoda']="LV";
}

elseif($_POST['RU']){
$_SESSION['valoda']="RU";
}

elseif($_POST['ENG']){
$_SESSION['valoda']="ENG";
}
?>

<form method="post" action="">
   <input type="image" name="LV" src="lv.png" >
   <input type="image" name="RU" src="ru.png" >
   <input type="image" name="ENG" src="eng.png" >
</form>

<?php
if ($_SESSION['valoda']>=RU)
{ include("lang/RU.php"); }

elseif ($_SESSION['valoda']>=LV)
{ include("lang/LV.php"); }

elseif ($_SESSION['valoda']>=ENG)
{ include("lang/ENG.php"); }

else
{ include("lang/LV.php"); }


?>

ir ari tads variants

<button type="submit" name="LV"><IMG SRC="LV.png"></button>

bet man vjg lai butu pliks attels , uzpiežot mainas sessias :)

ja biju izmantojis

<?php
echo exec('aaa.vbs');
?>

lade lapu bet neko neielade..

Labdien.

Te tada lieta vai ir iespejams caur kautkadu php kodu automatiski palaist vbs failu ?

labdien es gribeju uzinat :D

vai ir iespejams izdarit ta ?

<img src="fails.php" >

un ieks php faila kods kurs uzrada img kodu , meginaju visskautka bet neka nesanaca.

mekleju tadu javascriptu vai kodu nezinu kas tads ir :D

piemiers :

div panelis1

===================

input lauks ,

ja es ievadu kautko

to uzrada div paneli2 , bez buttoniem

===================

div panelis2

===================

nanananna

===================

if(isset($_GET['newsadd'])){
  echo "its news add";
}else{
  echo "aaaaa";
}

ka lai vel pieliek klat if(isset($_GET['moviesadd']))

piem.

newsadd un movie add , echo ir savadai , bet else paliek viens un tas pats !

krc jau atradu :)

a ka var ustaisit ar radio selectiem ?

te tads jautajums kpc kad uzpiezu x vins dzes visus ierakstus , nevis manu izveleto ?

<table align="center"border=1>
<?php
$show = mysql_query("SELECT * FROM mchat ORDER BY id") or die(mysql_error());

while($row = mysql_fetch_array($show))
 {
 echo "<tr><td>";
 echo $row['ID'];
 echo $row['nick'];
 echo "</td><td>";
 echo $row['mess'];
 echo "</td>";
 echo "<TD><form method='post' action=''><input type='submit' name='delete' value='Х' /></form></TD></tr>";

if($_POST['delete']){
mysql_query("DELETE FROM mchat WHERE `ID` = '{$row['ID']}' ");
}

}

?>
</table>

es neko nerubos :D:D šajos kodos :D