FT3

jau ustaisiju bet citadak izmantojot

<script type="text/javascript" src="http://code.jquery.com/jquery-1.4.2.min.js"></script>
<script type="text/javascript">
var auto_refresh = setInterval(function(){
$("#update").load('mysqlupdate.php').fadeIn("slow");
}, 30000);
</script>

ar php ifu var kautka apvienot ?

Labdien es nekad nebiju nodarbojies ar jqurijiem , man nekadigi nesanak izvest tekstu aa ieks php if , vai kads nevaretu palidzet ?

<script type="text/javascript" src="http://code.jquery.com/jquery-1.4.2.min.js"></script>
<script type="text/javascript">
   	var settimmer = 0;
   	$(function(){
           	window.setInterval(function() {
               	var timeCounter = $("b[id=show-time]").html();
               	var updateTime = eval(timeCounter)- eval(1);
               	$("b[id=show-time]").html(updateTime);
               	if(updateTime == 0){
              		document.write ("test");
               	}
           	}, 1000);
   	});
</script>
<div id="my-timer">
   	Page Will Redirect with in <b id="show-time">10</b> seconds      
</div>
<?php
$one = '<script>updateTime</script>';
$two = '0';
if($one == $two) { echo "aa"; }
?>

vai nu kautka citadak apvienot jquery ar php ^_^

Paldies iepriekš

ko tad isti meklet varat nosaukumu nosaukt , vai iz ka strada js or samting esle ?

gudrs gan esi

mekleju php sekunžu countdownu !

izdomaju taisisu ar time()

Sveiki te tada lieta , gribeju jautat ka var apvienot šos divus kodus , lai pec js refresh , taisitos update ?

<script>
<!--
//
var seconds=20
document.counter.d2.value='10'
function display(){
seconds-=1
if (seconds<=-1){
milisec=0
seconds+=1
document.location.href = '<?echo "$http/surfing.php?uid=$uid"; ?>';
}
else
document.counter.d2.value=seconds
setTimeout("display()",1000)
}
display()
-->
</script>

mysql_query("DELETE FROM `surfing` WHERE `surfcoins` = '0' ");
mysql_query("UPDATE `surfing` SET `surfcoins`  =  '$amount'  WHERE `homepage`  = '$homepage' ");
mysql_query("UPDATE `members` SET coins = '$amount2' WHERE ID = ".$_SESSION['wID']);

atrisinats vaina bija login forma :D

<?php
if (isset($_SESSION['wPassword']) && isset($_SESSION['wUsername'])) {$login="yes";}
else {$login="no";}
if($_GET['logout'] == "yes") {session_destroy();header('Location: .');}
if($_POST['login'] ) {header('Location: .');}
$result = mysql_query("SELECT * FROM `members` WHERE `id` = '$_SESSION[wID]'");
 if (mysql_num_rows($result)==1)
  {
$res = mysql_fetch_object($result);
$w_username = $res->username;
$w_email = $res->email;
$w_coins = $res->coins;

$w_id = $_SESSION[wID];
$_SESSION[wEmail] = $res->email;
$_SESSION[wCoins]  = $res->coins;
$_SESSION[wLevel]  = $res->level;
}
echo $w_username;
?>

izmet šadu kļudu , kur vaina ?

Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in C:\AppServ\www\traffic2\inc\user.php on line 10

daGrevis plds :)

netas :)

codez , njam neko citu izdomat nevareji ?

sveiki vai kads nevaretu iedot simple plus minus funkciju ?

njam plds ;/

wtf :D tur bija tads fails kurš palaiz ,vajadzigo failu man to vajag :D

sveiki gribeju jautat vai ir iespejam palaist jar failu iekš ftp servera ?

daudzos cs hostingos lietojas lai serveri butu ieslegts . neatceros tikai ka .

kads palidzes ? :D

nevairos :DDD palidzi please

nu ta ta ka tu teici maku . gribetos ta ka attela

http://www.bildites.lv/viewer.php?file=o5ci2m22v6r45pkq345i.bmp

un tur kur favorities izvest ciparus pa vienam ? ta var ?

nesapratu ;/

tatad ir viens jautajums

ka ustajsit favoritus

piem

fails1 id-1

fails2 id-2

un kad pievieno failu favoritam lai visi id ierakstas viena kolonaa iekš mysql

un ka pectam tos id izvest pa vienam

ja domens ir sasaldets un nau aktivs lietošana , nic uzradis ka ir brivs ;)

ne piem

ja datum ir 1

tad taisas update :)