Vo1The Posted March 9, 2011 Report Share Posted March 9, 2011 (edited) Skripta mērķis izvilkt pēdējos komentārus tākā man komentāri katrs savā tabulā un tabulas ir identiskas lietoju UNION , bet kā lai tagat izdara lai viņš atšķir no kuras tabulas viņš velk ārā ,jo links ir mainīgs ?id='.$links.'&'.$links2.'='.$id.' $sql = mysql_query("(SELECT * FROM jaunumu_com) UNION (SELECT * FROM video_com)"); piemēram ja tabula ir jaunumi : $links = news; $links2 = read; $id = $row[cid]; Bet ja tabula ir video tad $links = video; $links2 = wach; $id = $row; Edited March 9, 2011 by Vo1The Quote Link to comment Share on other sites More sharing options...
xPtv45z Posted March 9, 2011 Report Share Posted March 9, 2011 $sql = mysql_query("(SELECT *,'jaunumu_com' AS no_tabulas FROM jaunumu_com) UNION (SELECT *,'video_com' AS no_tabulas FROM video_com)"); Quote Link to comment Share on other sites More sharing options...
Vo1The Posted March 9, 2011 Author Report Share Posted March 9, 2011 $sql = mysql_query("(SELECT *,'jaunumu_com' AS no_tabulas FROM jaunumu_com) UNION (SELECT *,'video_com' AS no_tabulas FROM video_com)"); Labi velviens varinats kā $sql uzrakstīt , bet kā ar pārslēgu tikt galā ? Quote Link to comment Share on other sites More sharing options...
xPtv45z Posted March 9, 2011 Report Share Posted March 9, 2011 if(){}else{}? Quote Link to comment Share on other sites More sharing options...
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