des Posted October 25, 2004 Report Share Posted October 25, 2004 man izmeta Warning: Cannot modify header information - headers already sent by (output started at E:\Maajas_lapa\Zinja.php:1) in E:\Maajas_lapa\Zinja.php on line 19 Taatad zinja.php pirmajaa rindinjaa ir kaut kaads whitespeiss ieviesies.... centies vienmeer lai <?php ir pirmajaa rindinjaa un bez atstarpes no malas! Link to comment Share on other sites More sharing options...
bubu Posted October 25, 2004 Report Share Posted October 25, 2004 Daži ieteikumi: 1) neveido savus tegus (Zinja, Pamatfonts, ...) 2) linki jārāda relatīvie nevis absolūtie: <LINK REL="stylesheet" Href="file:///E|/Maajas_lapa/lemon.css" type="text/css"> <body background="file:///E|/Maajas_lapa/Pictures/back.jpg"> 3) aiz bgcolor jābūt = zīmei table tegā 4) aiz width="100% jābūt noslēdzošajai " pēdiņai .... Link to comment Share on other sites More sharing options...
leimis Posted October 25, 2004 Author Report Share Posted October 25, 2004 Paldies kungi, par ieteikumiem. Juus tagad varat hakot manu lapu kaa vien iepatiikaas. Man tagad jaaiet uz studentu korporaaciju. Buushu atpakalj tad reizi pa reizi buus jaatiek galaa ar sho sasaapeejushos probleemu Link to comment Share on other sites More sharing options...
leimis Posted October 27, 2004 Author Report Share Posted October 27, 2004 Esmu nochakareejies jau divas dienas bet rezultaats nulle. Varbuut probleema nav kodaa. Bet kaut kur fiziski Apacii vai MySql vai PHP. It kaa viss ir konfigureets peec graamatas un sarezhgjiijumiem nevajadzeetu buut. mysql_fetch_array(): supplied argument is not a valid MySQL result resource shitas errors jau man chakaree praatu es nezinu zajebal jau visa shii padariishana Link to comment Share on other sites More sharing options...
рпр Posted October 27, 2004 Report Share Posted October 27, 2004 tur jau taa lieta, ka peec graamatas, ja kautko maina, tad pasham jaasaprot, ko maina, savaadaak taada eksperimenteeshana var novest liidz nepatiikamam rezultaatam. protams uz test kasteem utt taa ir normaala paraadiiba, bet uz reaaliem serveriem neiesaku eksperimenteet. paskaties <?php phpinfo(); ?> vai tev vispar straadaa php, ir visi nepiecieshamie modulji un kaa tur viss nokonfigureets. Link to comment Share on other sites More sharing options...
bubu Posted October 27, 2004 Report Share Posted October 27, 2004 mysql_fetch_array(): supplied argument is not a valid MySQL result resource Šis errors rādās tad, kad nekorekts SQL teikums padots. Izsauc mysql_error() funkciju un paskaties, ko šī saka ;) Link to comment Share on other sites More sharing options...
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