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SQL pieprasījumā apzināti netiek lietots LIKE BINARY , lai atrastos arī 'līdzīgie' ieraksti. Bet regexp, protams nav tik pielaidīga. 

Kā būtu jāuzlabo funkcija, lai marķējas visi noķertie 'fragmenti'?!

Quote

return preg_replace("/".preg_quote($crit, "/")."/i", "<span class='text-danger text-bold'>$0</span>", $text);

Paldies!

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