Sangsom Posted February 3, 2011 Report Share Posted February 3, 2011 Sveiki atkal.. Vēlreiz saskaros ar problemu kas saistīta ar PHP versiju. No grāmatas ir sekojošas koda rindas, kuras strādā no 5.2 versijas, bet man ir 5.1.6 gribu zināt kā to pašu var paveikt manā versijā. if (filter_has_var(INPUT_POST, "people")){ showPeople(); } // un $formData = filter_input_array(INPUT_POST); $people = $formData["people"]; par pirmo rindiņu man ir skaidrs if (isset($_POST["people"])){ showPeople(); jau citā topika uzzinaju, kā vajg bet nezinu kā tikt gala ar otro rindu tieši ar filter_input_array(INPUT_POST) Paldies. Quote Link to comment Share on other sites More sharing options...
Blitz Posted February 3, 2011 Report Share Posted February 3, 2011 //$formData = filter_input_array(INPUT_POST); $people = $_POST["people"]; Quote Link to comment Share on other sites More sharing options...
Sangsom Posted February 3, 2011 Author Report Share Posted February 3, 2011 //$formData = filter_input_array(INPUT_POST); $people = $_POST["people"]; Ģeniāli, lielais paldies ) Quote Link to comment Share on other sites More sharing options...
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