marlboro Posted December 10, 2008 Report Share Posted December 10, 2008 Kā var panāk ka php automatiski no db izvelk vissus id un define ja id ir tadz ka izvilkts tad echo 'selected' shini gadijuma ja $lapa==ar tadu ka db ieraxtits <select name="lapa" onchange="document.forms['select_content'].submit();"> <option value="0" <?php if ($lapa==0) echo 'selected';?>></option> <option value="1" <?php if ($lapa==1) echo 'selected';?>>Banner : 1</option> <option value="2" <?php if ($lapa==2) echo 'selected';?>>Banner : 2</option> <option value="3" <?php if ($lapa==3) echo 'selected';?>>Banner : 3</option> <option value="4" <?php if ($lapa==4) echo 'selected';?>>Banner : 4</option> </select> Link to comment Share on other sites More sharing options...
Aleksejs Posted December 10, 2008 Report Share Posted December 10, 2008 Sveiks! Vispirms atlasi rezultātu ar visiem id. SELECT id FROM tabula ORDER BY id Tad ciklā lasi pa vienai rindai. while ($rinda = mysql_fetch_row($rez)){ echo '<option value="'.$rinda['id'].'"'.($rinda['id']==$lapa ? ' selected' : '').'>Banner '.$rinda['id'].'</option>'; } Link to comment Share on other sites More sharing options...
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