PHP "programmētajas" esmu 7 dienas
ta ka lūdzu neizmejiet mani parāk
problēma šada izvelku no tabulas datus kur vinai daļai datu pilna nosaukuma vieta ir ID kada veida lai es pārvešu ID nosaukumā
<?
$ievacampasutijumums="SELECT * FROM pasutijumi";
$result=mysql_query($ievacampasutijumums);
$num=mysql_numrows($result);
mysql_close();
$i=0;
print "
<table width='700' border='0' align='center' cellpadding='0' cellspacing='1'>
<tr bgcolor='#CCCC00'>
<td width='106'>Company</td>
<td width='348'>Head</td>
<td width='53' align='center'>Files</td>
<td width='92' align='center'>Date f </td>
<td width='95' align='center'>Date to </td>
</tr>
";
while ($i < $num) {
$pasid=mysql_result($result,$i,"slu_id");
$pashed=mysql_result($result,$i,"head");
$_pashead=mysql_result($result,$i,"bodyone");
$_pasdatef=mysql_result($result,$i,"bodytwo");
$paskatid=mysql_result($result,$i,"cat_id");
$pasorid=mysql_result($result,$i,"comp_id");
$pasdatef=mysql_result($result,$i,"date_from");
$pasdatet=mysql_result($result,$i,"date_to");
print "
<tr>
<td>$pasorid</td>
<td>$pashed</td>
<td> </td>
<td>$pasdatef</td>
<td>$pasdatef</td>
</tr>";
$i++;
}
print"</table>";
?>