drellout

Paldies, bilde tiek uplaadota ar formatiem. Vel joprojam ir problema http://paste.php.lv/65df2c92ba95c29950872847c71007fc?lang=php Vai ludzu kads varetu izlabot skriptu, lai tie cilveki kuriem ir bilde mapee style/uploads/ ar vinju niku nosaukumu radaas profilaa, ja nee tad $def_pic. Paldies

Man uplaadojot bildes sanaca tik tizli. Uploado bildi ar nosaukumu tads kads useram, bez jpg. piem vnk m8t

Es sataisiju šadi $avatar = '/style/uploads/".$req_user_info["username"]."'; if (file_exists($avatar)) { $avatar = $req_user_info["username"]; }elseif(!empty($avatar)) { $avatar = 'noavatar.png'; } ču čūč podaļše echo "<img align='right' class='photo_author' style='margin-top: -35px;' src='style/uploads/".$avatar."' width='120' height='100' alt='Bilde' />"; Visas bildes ir ka noavatar, palidzat, noradat manu kludu ludzu. Paldies.

Man vispar nav nekads db sakars Es satasiju taa - $req_user_info['username'] = $taachaljaniks; if(files_exists("/style/uploads/".$taachaljaniks)) { print "<img src='/style/uploads/".$taachaljaniks."' />"; } elseif(!empty($taachaljaniks)) { print "<img src='".$taachaljaniks."' />"; } else { print "<img src='".$def_pic."' />"; } Errors Fatal error: Call to undefined function files_exists() in C:\AppServ\www\userinfo.php on line 32 32 rinda if(files_exists("/style/uploads/".$taachaljaniks)) {

Nu es esmu iesacejs, bet doma tada ja mape uploads ir lietotaja varda fails, tad vinsh tiek inkludots, ja nav tad avatar_def tiek

Es esmu izveidojies kautkadu diezgan nestradajoshu skriptu. Man vajadzigs, lai butu tā - ja lietotajam nav mape uploads/images/ vinja nosaukuma fails tad bilde iet $avatar_def = http://......, bet ja ir tad vinsh njem to failu... Man rada visus kas ir uplaadoti, rada tam kas tagad ir ielogojies, bet nerada citiem, vinji nez kapec grib njemt to bildi, bet vinjas nav. Rekur kods. $default_avatar = 'noavatar.png'; /* Username */ $avatar = $path= "".$req_user_info['username'].""; if ($avatar = $path= "".$req_user_info['username']."") echo "".$req_user_info['username'].""; else{ $avatar = $default_avatar; } echo "<b>Lietotajs: ".$req_user_info['username']."</b><br>"; echo "<b>Vards: ".$req_user_info['name']."</b><br>"; echo "<img align='right' class='photo_author' style='margin-top: -35px;' src='image/uploads/".$avatar."' width='120' height='100' alt='Bilde' />"; echo "<b>Vecums:</b>$age<br>"; echo "<b>Email:</b> ".$req_user_info['email']."<br>"; Palidzat ludzu izlabot šo skriptu, vai uzrakstat lūdzu jaunu. Paldies.

ko man tad darīt ?

a tu domaa kas man ir datubazee ?? ok... karo4 video datubazee ir vidrate sadalja kuraa ir id int(11) Нет auto_increment video_id text utf8_general_ci Нет video_rating text utf8_general_ci Нет vote text utf8_general_ci Нет user_ip varchar(100) utf8_general_ci Нет un vel video datubazee video sadaljaa Поле Тип Сравнение Атрибуты Ноль По умолчанию Дополнительно Действие id int(11) Нет auto_increment nosauk text utf8_general_ci Нет video text utf8_general_ci Нет autors text utf8_general_ci Нет apraksts text utf8_general_ci Нет kategorijas varchar(20) utf8_general_ci Нет vidrate struktura : id video_id video_rating vote user_ip 162 170 5 83.99.192.13 164 170 5 83.99.192.11 165 170 5 83.99.192.10 166 170 5 83.99.192.14 bet webaa raada tikai 1 vote un vote 5

es manuaali pievienoju datubazee ratingus tur 5, 1 kkadam video, un izvada tikai 1 pirmo

Labs vakars, es atvainojos. Es gribētu paprasīt lai kāds izlabo skriptiņu. REKUR KODS Tas ir skripts (balsoshanas) Nestradaa tas ka, vinsh nesummee kopaa balsoshanas

vai vnk samainiit header('Pragma: no-cache'); uz ob_start('Pragma: no-cache');

kur jāliek pirms taam rindiņam kur header sākās ?

Labdien. Es atvainojos ja bija šis temats jau... Es internetā atradu rating skriptu, ieinkludoju webaa un met šādus erorus Warning: Cannot modify header information - headers already sent by (output started at C:\AppServ\www\index.php:8) in C:\AppServ\www\rating\cls_rate.php on line 278 Warning: Cannot modify header information - headers already sent by (output started at C:\AppServ\www\index.php:8) in C:\AppServ\www\rating\cls_rate.php on line 279 Warning: Cannot modify header information - headers already sent by (output started at C:\AppServ\www\index.php:8) in C:\AppServ\www\rating\cls_rate.php on line 280 Warning: Cannot modify header information - headers already sent by (output started at C:\AppServ\www\index.php:8) in C:\AppServ\www\rating\cls_rate.php on line 281 Warning: Cannot modify header information - headers already sent by (output started at C:\AppServ\www\index.php:8) in C:\AppServ\www\rating\cls_rate.php on line 282 Warning: Cannot modify header information - headers already sent by (output started at C:\AppServ\www\index.php:8) in C:\AppServ\www\rating\cls_rate.php on line 284 Es biju lasījis visādus topikus, bet neko nejēdzu, varētu vieglāk palīdzet, tā lai es varētu saprast... Tie kuri grib uzrakstīt "go google.lv" vai vel kkādas muļķības kā ej mācies u.t.t tie var vnk iet turpināt lasīt grāmatas

Paldies Aleksej, starpc mani ar sauc Aleksejs ;D. Visu sametu vienā mapē itkā tgd nemet erorus :)

ir rename, tgd met āra šitādu eroru Warning: rename(C:\WINDOWS\TEMP\php11D.tmp,files/FL056.zip) [function.rename]: No such file or directory in C:\AppServ\www\inc\upload\upload.php on line 16 File could not be uploaded

Atvaino, bet es nesapratu, vai lūdzu vari palīdzēt tā lai es apmēram saprastu kas ir jāedito ?

Laba nakts, php.lv lietotāji es hot skriptā atradu upload sistēmu, bet sastapos ar vienu problēmu, bet tā itkā viss strādā <?php $allowed = array("jpeg","gif","png","bmp", "jpg", "rar", "exe", "jpg", "hltv", "dem", "txt", "zip"); ?> <form action="" method="post" enctype="multipart/form-data"> Choose file to upload <input name="upload" type="file"> <input name="sb" id="sb" value="Upload" type="submit"> </form> <?php if(isset($_POST['sb'])) { //check for valid extension $pathInfo = pathinfo($_FILES["upload"]["name"]); $extension = $pathInfo['extension']; //choose directory/foolder to place the file in $dir = "files"; if(!in_array($extension, $allowed)) die("Extension not allowed!"); if(move_uploaded_file($_FILES['upload']['tmp_name'], "$dir/".$_FILES['upload']['name'])) { print "Your new file can be viewed/download at <input name=\"newfile\" value=\"http://$_SERVER[HTTP_HOST]/inc/upload/$dir/".$_FILES['upload']['name']."\" type=\"text\" style=\"width: 300px\">"; }else{ print "File could not be uploaded"; } $DatabaseHost = "localhost"; $DatabaseUsername = "root"; $DatabasePassword = "pw"; $DatabaseName = "file"; $connection = mysql_connect($DatabaseHost, $DatabaseUsername, $DatabasePassword) or die("Cannot connect to MySQL!"); mysql_select_db($DatabaseName, $connection) or die("Cannot find database!"); $sql = "insert into files values (null, '".htmlentities($_FILES['upload']['name'])."', 'now()', '$_SERVER[REMOTE_ADDR]')"; $rs = mysql_query($sql); print mysql_error(); } ?> <br/> Kad tajā skriptā ej piemēram http://ip/inc/upload/index.php tad viss ok viss iet, bet kad sataisa lai viņš gruzītos/inkludotos webā tad met ārā erorus Warning: move_uploaded_file(files/FL052.zip) [function.move-uploaded-file]: failed to open stream: No such file or directory in C:\AppServ\www\inc\upload\upload.php on line 16 Warning: move_uploaded_file() [function.move-uploaded-file]: Unable to move 'C:\WINDOWS\TEMP\phpFB.tmp' to 'files/FL052.zip' in C:\AppServ\www\inc\upload\upload.php on line 16 File could not be uploaded

Paldies problēma tika izrisināta

Laba nakts ! es te sastapos ar probleemu <?php function dbConnect(){ mysql_connect("localhost","root","pw"); mysql_select_db("clanwars"); if(isset($_POST['edit'])){ if(!empty($_POST['km2']) && !empty($_POST['km1_rez'])&& !empty($_POST['km2_rez'])&& !empty($_POST['km2_taut'])&& !empty($_POST['karte'])&& !empty($_POST['cikxcik'])&& !empty($_POST['tip'])){ $km2 = mysql_real_escape_string($_POST['km2']); $km1_rez = mysql_real_escape_string($_POST['km1_rez']); $km2_rez = mysql_real_escape_string($_POST['km2_rez']); $km2_taut = mysql_real_escape_string($_POST['km2_taut']); $karte = mysql_real_escape_string($_POST['karte']); $cikxcik = mysql_real_escape_string($_POST['cikxcik']); $tip = mysql_real_escape_string($_POST['tip']); $kve = mysql_query("UPDATE cw SET km2=$km2, km1_rez=$km1_rez, km2_rez=$km2_rez, km2_taut=$km2_taut, karte=$karte , cikxcik=$cikxcik , tip=$tip") or die(mysql_error()); if($kve == true){ echo "editots!";} if($kve == false){ echo "Kkads suds !";} }else{echo "huj";} } while($cw = mysql_fetch_array($select_cw)){ ?> <form action="" method="post"> <input name="km2" type="text" value="<?php echo $cw['km2']; ?>"><br/> <input name="km1_rez" type="text" value="<?php echo $cw['km1_rez']; ?>"><br/> <input name="km2_rez" type="text" value="<?php echo $cw['km2_rez']; ?>"><br/> <input name="km2_taut" type="text" value="<?php echo $cw['km2_taut']; ?>"><br/> <input name="karte" type="text" value="<?php echo $cw['karte']; ?>"><br/> <input name="cikxcik" type="text" value="<?php echo $cw['cikxcik']; ?>"><br/> <input name="tip" type="text" value="<?php echo $cw['tip']; ?>"><br/> <input name="edit" type="submit"></form><?php } ?> neko nerāda vnk baltu lapu Būtu ļoti pateicīgs ja jūs man spētu palīdzēt

apmēram sapratu, un kā tālāk darīties ? :D Atvaino bet es gandrīz php nerubiju

Aizmirsu pateikt km2 - pretinieku komanda un parejais lkm zinat #2 Tu man uzdod jautājumu :D es vsp nezinu

Labs vakars... Es gribētu jums paprasīt, vai drizāk palūgt lai kāds varētu pateikt kā var izdzēst kko no sql neieejot viņa ar kādu kodu Man bija doma izveidot kaut ko tādu <strong>Ko dzēst ?</strong><br> <select name="clanwars" size="1" > <option value="1aiscw">1tm vs 2tm</option> <option value="2aiscw">1tm vs 2tm</option> ..... un tadaa garaa lai pats liek cik ir </select> </form> Lai viņš velk ārā cik ir tie piemēram clanwari un izvēloties viņu un tad uzspiežot pogu dzēst viņš izdzēšās Pašam ir tāds sql fails CREATE TABLE `cw` ( `km2` text NOT NULL, `km1_rez` text NOT NULL, `km2_rez` text NOT NULL, `km2_taut` text NOT NULL, `karte` text NOT NULL, `cikxcik` text NOT NULL, `id` int(10) NOT NULL auto_increment, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=15