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false

Reģistrētie lietotāji
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  1. index.php fails

    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
    <html>
    <head>
    <title>title</title>
    <meta http-equiv="content-type" content="text/html; charset=UTF-8" />
    <script type="text/javascript" src="/js.js"></script>
    </head>
    <body>
    <div class="rand">
    <a href="javascript:;" onclick="load_someone_said(); return false;"><img src="efresh.gif" style="border: 0pt none ;"></a>
    <?php include("rand.php"); ?></div>
    </head>
    </html>
    

     

    rand.php

    <?php
    rand(4,412); 
    ?>

    js.js fails

    function load_monitor() {
    $("#rand").html('<img style="background-position: center;" src="http://heal.lv/style/web_images/spinner.gif">');
    $("#rand").load("rand.php");
    }
    

    Problēma ir tāda kā viņš negrib neko refrešot?

  2. <?php
    /konekt
    session_start();
    error_reporting(E_ALL);
    include("func.php");
    $md5 = md5($_SERVER['REMOTE_ADDR']);
    if(isset($_SESSION['id']))
    {
    $id = $_SESSION['id'];
    $result = mysql_query("SELECT * FROM lietotaaji WHERE id=$id");
    }
    if(isset($_GET['login']) and $_GET['login'] == "".$md5."")
    {
    $niks = quote_smart($_POST['niks']);
    $parole = quote_smart(md5($_POST['parole']));
    $result = mysql_query("SELECT * FROM lietotaaji WHERE niks=$niks and parole=$parole");
    $row = mysql_fetch_row($result);
    $id = $row[0];
    if(mysql_num_rows($result) == 1)
    {
    $taim = time();
    mysql_query("UPDATE lietotaaji SET last_a=$taim WHERE id=$id");
    $_SESSION['id'] = $id;
    }
    else
    {
    $nav = "<div class=\"error\">Nepareizs niks un/vai parole!</div>";
    }
    }
    ?>
    
    <?php
    if(!isset($_SESSION['id']))
    {
    ?>
    <h2>Lietotājiem</h2><div class="menu_cont">
    <div id="login">
    <?php
    if(isset($nav)){
    echo $nav;
    }
    ?><br/>
    <form action="/?login=<?php echo $md5; ?>" method="post">
    Niks:<br/><input name="niks" type="text"><br/>
    Parole:<br/><input name="parole" type="password"><br/>
    <input name="login" type="submit" value="Ielogoties!"><br/><a href="/reg/">Reģistrēties</a> - <a href="/forgot_pw/">Aizmirsi paroli?</a> 
    </form>
    </div></div>
    <?php
    }
    if(isset($_SESSION['id']))
    {
    ?>
    <h2>Sveiks</b></h2><div class="menu_cont">
    <div id="login">
    tu esi ielogojies!
    </div></div>
    <?php
    }
    ?>

    Bet ielogoties nevar, rada kā nepareiza parole vai/un niks. Esmu meiģinājis ar pareizo akountu kas ir reģistrets datubāzē, gan ar nepareizo, kas nav.

    Kas kodā ir nepareizs?

  3. <?
    $sql = mysql_query("SELECT * FROM tabula");
    while($r=mysql_fetch_array($sql)){
    echo "<img src=\"".$r['bilde']."\"><br/>".$r['vards']." ".$r['uzvards']."";
    }
    ?>
    

    a?

  4. Kods:

    <?php
    if(isset($_GET['op']) && $_GET['op'] == 'atdot'){
    echo "Kam tu gribi atdot naudu?<br/><input name='lietotaajs' type='text'><br/>Cik tu gribi atdot?<br/><input name='cik' type='text'><input name='submjit' type='submit' value='Aizdot!'><br/>";
    }
    if(isset($_POST['submjit'])){
    $l_co = $jor['coins'];
    $l_coins = $_POST['cik'];
    if($l_coins > $l_co){
    echo "Aizsūtīts!";
    $dadads = mysql_query("SELECT * FROM lietotaaji WHERE niks=".$_POST['lietotaajs']."");
    while(mysql_fetch_array($dadads)){
    $liet_coins = $kasd['coins'];
    $sn_id = $kasd['id'];
    $user_c_a = $l_co-$l_coins;
    $da_c = $liet_coins+$l_coins;
    mysql_query("UPDATE lietotaaji SET coins=".$da_c." WHERE id=".$sn_id."");
    mysql_query("UPDATE lietotaaji SET coins=".$user_c_a." WHERE id=$id");
    }
    }else{
    echo "<div class=error>Tev nepietiek naudas!</div>";
    }
    }
    }
    ?>
    

    Bet nekas neupdeitojas datubāzē.. Kāds var pateikt, kas par kļūdu?

  5. Kas ir jaizlabo css kodā lai tabulas būtu tapat kā attelā, nevis rindiņa uz lēju?

    Css

    .tabuula {
    color: #000;
    background-color: #F0F0F0;
    padding: 5px;
    width: 130px;
    margin-top: 1px;
    margin-bottom: 1px;
    margin-left: 0px;
    border: 1px solid #acbdd2;
    }

     

    Un mājaslapas kods

    <div class="tabuula"><b>..</b> 1/2<Br>
    <img src="/image/maps/<?php echo $rob['mape2']; ?>.png">
    </div>
    

    post-4101-125898408071_thumb.jpg

  6. // Konekcija
    
    $selekts = mysql_query("SELECT * FROM ibf_sessions WHERE member_id=".$_COOKIE['member_id']) or mysql_error();
    $r = mysql_fetch_array($selekts);
     if(isset($_POST['ierakstiit'])) {
       $ieraksts = $_POST['ieraksts'];
       $laiks = time();
       $membera_niks = $r['member_name'];
       mysql_query("INSERT INTO chats (ieraksts, laiks, niks) VALUES ('$ieraksts','$laiks','$membera_niks')") or mysql_error();
    
    }
    
    if($_COOKIE['member_id'] = 0) {
     echo '
    <form action="" method="post">
    <input type="text" name="ieraksts" />
    <input type="submit" name="ierakstiit" />
    </form>
     ';
    }
    
    $dati = mysql_query("SELECT * FROM chats ORDER BY laiks DESC LIMIT 20 ") or mysql_error();
    $er = mysql_fetch_array($dati);
     echo "<font style=\"color:green;\">".$er['niks']."</font><br>";
     echo $er['ieraksts']."<br />";
    

    un kā ar šo?

  7. mysql_query("INSERT INTO chats (ieraksts, laiks, niks) VALUES ('$ieraksts','$laiks','$membera_niks')");

    uz

    mysql_query("INSERT INTO chats (ieraksts, laiks, niks) VALUES ('$ieraksts','$laiks','$membera_niks')") or mysql_error();

    Un paradi ko rada?

  8. Nezinu kas notiek, bet jebkadā kodā rada eroru:

     

    Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in C:\xampp\xampp\htdocs\index.php on line 271

    $viesi = mysql_num_rows(mysql_query("SELECT * FROM lietotaaji WHERE id = '0' and time >= ".$delays.""));

     

    Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\xampp\xampp\htdocs\index.php on line 252

    $entity = mysql_fetch_array(mysql_query("SELECT * FROM lietotaaji WHERE id={$_SESSION['id']}"), MYSQL_ASSOC);

     

    Kāda vaina?

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