GeRik
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Posts posted by GeRik
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kad maacijos php no evgeni papov video kursa tur nekas tads nebij tapec arii ta nevaru zinat
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nu ja pieliku bet kads var kadu piemeru uzmest ?
ka tur iet visi tie UPDATE $_POST u.t.t
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Pienemsim ja es izveidoju IPB Foruma datubaze jaunu tabulu ar
struktru pienemsim
Vards
uzvards
dzimshanas Dati u.t.t
Bet ka man izdarit lai tas butu atsevishki katram lietotajam un lai citi lietotaji arii varetu uz to apstiities piemeram shadi profils kur ir vinja informacija kur vinsh to var mainiit a apskate uz citiem lietotajiem shadi
pie lietotajiem ka mana gadijuma memberi.php un lai katra member info varetu redzet piemeram member.php?id=1
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atradu atrisinajumu :)
<form action='/forum/index.php?act=Login&CODE=01&return=http://sixsixone.oo.lv/' method='post' name='LOGIN'>
Bet ka to izdarit ar logout ? :O
<a href= 'forum/index.php?act=Login&CODE=03&k=".$logout."'>[iZIET]</a>";
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maldies jo ja caur forumu ielagosies tad vinsh tak aizmetis uz web lapu bet man vaig ja caur web lapu tikai ja ielagojas ka vinju nemet uz forumu bet paliek turpat
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man gan kka nau smuki varbut varetu ielikt savejo mazliet pielaboto? :)
prasi pa skype gw-gerik :)
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Sheit pasties links bet man ir nedaudz pielabots kads nezin ka uzlikt piemeram ja vinjam avatara nav lai butu kkada defaulta bildiite >
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iekope sava StyleSheet faila
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Ok :) gaidishu
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lai var pienemsim skatities ta 23 Memberi viena lapa Spiez pienemsim 2 un tur ir nakamie 23 memberi u.t.t vai arii vnk Nakama Lapa
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Wuu a tu klat negribi pielikt lai var skirstit lapas ?
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man ir atsevishki ielikts taka tip caur <?include ("login.php");?>
luuk viss login.php
<?php mysql_connect("localhost", "root", "parole"); mysql_select_db("forum"); $id = $_COOKIE['member_id']; $dati= "SELECT * FROM `ibf_members` WHERE id = $id LIMIT 1"; $dati1=mysql_query($dati) or mysql_error(); $dati2= mysql_fetch_array($dati1); $logout = md5($dati2['email']."&".$dati2['member_login_key']."&".$dati2['joined']); if(isset($_COOKIE['member_id'])){ $get=mysql_query("SELECT * FROM `ibf_members` WHERE id='".intval($_COOKIE['member_id'])."'") or die(mysql_error()); $udata=mysql_fetch_object($get); if($udata->member_login_key==$_COOKIE['pass_hash']) { echo " <center>Čau, <b>".$udata->members_display_name."</b></center><br> <a href= 'http://sixsixone.oo.lv/'>Pievienot reklamu</a><br> <a href= 'http://sixsixone.oo.lv/forum/index.php?act=Msg&CODE=01'>Vēstules</a><br> <a href= 'http://sixsixone.oo.lv/forum/index.php?act=UserCP&CODE=00'>Labot Profilu</a><br> <a href= 'http://sixsixone.oo.lv/forum/index.php?act=Members'>Lietotāji</a><br> <a href= 'http://sixsixone.oo.lv/forum/index.php?act=Search&f=0'>Meklēt forumā</a><br> <a href='irc://irc.lv/sixsixone'><font color=red>#sixsixone mIRC</font></a><br><br> <a href= 'forum/index.php?act=Login&CODE=03&k=".$logout."'>[iZIET]</a>"; }else{ echo " <form action='/index.php'> <form method='post' action='http://sixsixone.oo.lv/forum/index.php?act=Login&CODE=01' name='LOGIN'> <b>Lietotajvards:</b><br> <input style='width: 124px;' name='UserName' type='text'><br> <b>Parole:</b><br> <input style='width: 124px;' name='PassWord' type='password'><br> <b>acereties mani?</b> <input name='CookieDate' value='1' type='checkbox'><br> <input value=' ienakt ' name='CookieDate' type='submit'><a href=http://sixsixone.oo.lv/forum/index.php?act=Reg&CODE=00'> Registreties</a> </form>"; } }else{ echo " <form action='/index.php'> <form method='post' action='http://sixsixone.oo.lv/forum/index.php?act=Login&CODE=01' name='LOGIN'> <b>Lietotajvards:</b><br> <input style='width: 124px;' name='UserName' type='text'><br> <b>Parole:</b><br> <input style='width: 124px;' name='PassWord' type='password'><br> <b>acereties mani?</b> <input name='CookieDate' value='1' type='checkbox'><br> <input value=' Ienakt ' name='CookieDate' type='submit'><a href=http://sixsixone.oo.lv/forum/index.php?act=Reg&CODE=00'> Registreties</a> </form>"; } ?> -
es novacu 33 Linija @ ziimiti(tagad izmantoju nedaudz savadak un ir 2 errori)
1 rada ka janodefine bet man 4ota nesanaca un otrs ir
Warning: mysql_fetch_object(): supplied argument is not a valid MySQL result resource in C:\AppServ\www\memb.php on line 37 Notice: Undefined index: p in C:\AppServ\www\memb.php on line 50
Luuk links uz jauno script nevaretu ludz kads to kluudu izlabot ?
http://paste.php.lv/7327c9c1163e52f0c1892a470ca648f0?lang=php
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bet es tak jau skatijos kur notiek login funkcija pierakstiju klat beigas izskatijas shadi
<form action='/index.php'> <form method='post' action='http://sixsixone.oo.lv/forum/index.php?act=Login&CODE=01' name='LOGIN'> <b>Lietotajvards:</b><br> <input style='width: 124px;' name='UserName' type='text'><br> <b>Parole:</b><br> <input style='width: 124px;' name='PassWord' type='password'><br> <b>acereties mani?</b> <input name='CookieDate' value='1' type='checkbox'><br> <input value=' Ienakt ' name='CookieDate' type='submit'><a href=http://sixsixone.oo.lv/forum/index.php?act=Reg&CODE=00'> Registreties</a> </form>";
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pielika un man vairs nevarej ielagoites
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noavacu un nekas neparadijas
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Nesaprotu kur ir kljuuda man vnk neuzrada iespeju shkirstiit lapas
http://paste.php.lv/0cf9ae0372755a9de41b7a7f35ce2198?lang=php
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seko manam darbibam man vismaz sanaca uzchinit
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Nodefineju itka vis aizgaja bet neuzrada visus memberus un ka vinjus varetu sadalit pa lapam ?
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vari nedaudz vairak aprakstit ka to izdarit un ko tu ar to domaji
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Luk nu kas man sanaca tagad
<?php error_reporting(E_ALL); ini_set('display_errors', 1); $sql_host = "localhost"; $sql_user = "root"; $sql_pass = ""; $sql_database = "forum"; define('WWW','www'); if (!defined('WWW')) { header('Location: http://'.$_SERVER['HTTP_HOST'].''); die(); } $link = mysql_connect($INFO['sql_host'],$INFO['sql_user'],$INFO['sql_pass']); mysql_query('use '.$INFO['sql_database'].';'); $page = '<div id="userlist">'; $result = mysql_query('select t1.id,t1.members_display_name,t2.avatar_location from '.$INFO['sql_tbl_prefix'].'members t1 join '.$INFO['sql_tbl_prefix'].'member_extra t2 on (t1.id = t2.id) limit 10;'); if (!empty($result)) { while ($r = mysql_fetch_array($result)) { $page .='<p> <a href="'.WWW.'forum/index.php?showuser='.$r[0].'"> <img class="avatar" src="'.WWW.'forum/uploads/'.$r[2].'" alt="'.$r[1].'" /> '.$r[1].'</a> </p>'; } } $page .='</div>'; echo $page; mysql_close($link); ?>un lapa rada tagad
Notice: Undefined variable: INFO in C:\AppServ\www\lietotaji.php on line 11 Notice: Undefined variable: INFO in C:\AppServ\www\lietotaji.php on line 11 Notice: Undefined variable: INFO in C:\AppServ\www\lietotaji.php on line 11 Notice: Undefined variable: INFO in C:\AppServ\www\lietotaji.php on line 12 Notice: Undefined variable: INFO in C:\AppServ\www\lietotaji.php on line 15 Notice: Undefined variable: INFO in C:\AppServ\www\lietotaji.php on line 15
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Luk ko rada Source koda
<div id="userlist"></div>
un ka man ir tas vis uzrakstic
<? define('WWW','www'); if (!defined('WWW')) { header('Location: http://'.$_SERVER['HTTP_HOST'].''); die(); } $link = mysql_connect($INFO['sql_host'],$INFO['sql_user'],$INFO['sql_pass']); mysql_query('use '.$INFO['sql_database'].';'); $page = '<div id="userlist">'; $result = mysql_query('select t1.id,t1.members_display_name,t2.avatar_location from '.$INFO['sql_tbl_prefix'].'members t1 join '.$INFO['sql_tbl_prefix'].'member_extra t2 on (t1.id = t2.id) limit 10;'); if (!empty($result)) { while ($r = mysql_fetch_array($result)) { $page .='<p> <a href="'.WWW.'forum/index.php?showuser='.$r[0].'"> <img class="avatar" src="'.WWW.'forum/uploads/'.$r[2].'" alt="'.$r[1].'" /> '.$r[1].'</a> </p>'; } } $page .='</div>'; echo $page; mysql_close($link); error_reporting(E_ALL); ini_set('display_errors', 1); ?> -
uzrakstiju vienalga balta lapa
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ja jau tur ir Kļūda tad kā es varu vinju izvadīt ja es pat nezinu kur vinja ir
izvadiju un neko neparadij lietoju error_reporting(E_ALL);
Palidziba + vai manas domas ir pareizas?
in Iesācējiem
Posted
nesapratu scripts ka var but zagts ja vinsh tiek ielikts sheit pahodu tieshi tur arii atradu un es prasiju vai pareiza doma a ne lai tu uztaisiitu :D