Gunchaz Posted January 19, 2005 Report Share Posted January 19, 2005 <? $filename = 'poga.gif'; $degrees = 18; header('Content-type: image/jpeg'); $source = imagecreatefromjpeg($filename); $rotate = imagerotate($source, $degrees, 0); imagejpeg($rotate); ?> izvadaas bildiite skiibi !!! Zuper duper. Bet vajag taa lai taa buutu podzinja, un vajag lai nospiezot lido uz kaukaadu linku. Jautaajums taads kaa pieskirt linku bildiitei tipa mainiigajam $rotate ?! Link to comment Share on other sites More sharing options...
рпр Posted January 19, 2005 Report Share Posted January 19, 2005 tā nevar. to var ar htmlu izdariit, iekhs <a href="links.html"><img src="fails.php"/></a> jānorāda php skripts (fails.php), kas to bildi parādīs. ja vajag podzinja, tad <input type="image" src="fails.php"/> Link to comment Share on other sites More sharing options...
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