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Ajax Upload


sandrulis
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Sveiki! neliela problēma saistībā ar ajax upload.

 

Izmantoju tikai ar javascript failu:

(function () {
	var input = document.getElementById("images"), 
		formdata = false;

	if (window.FormData) {
    formdata = new FormData();
    document.getElementById("btns").style.display = "none";
	}
	
 	input.addEventListener("change", function (evt) {
 		var i = 0, len = this.files.length, img, reader, file;
	
		for ( ; i < len; i++ ) {
			file = this.files[i];
	
			if (!!file.type.match(/image.*/)) {
				if ( window.FileReader ) {
					reader = new FileReader();
					reader.onloadend = function (e) { 
						showUploadedItem(e.target.result, file.fileName);
					};
					reader.readAsDataURL(file);
				}
				if (formdata) {
					formdata.append("images[]", file);
				}
			}	
		}
	
		if (formdata) {
			$.ajax({
				url: "upload.php",
				type: "POST",
				data: formdata,
				processData: false,
				contentType: false,
				success: function (html) {
				$("#images_list").append(html);
				$('#images').attr({ value: '' });
				}
			});
		}
	}, false);
}());

un problēma ir tāda, ka augšuplādējot vienu bildi viss ok, bet kad gribu norādīt vēl vienu tad viņš augšuplādē atkal iepriekšējo un tad atkal norādīto?

 

kur ir problēma?

Lai neaugšuplādētu atkal jau iepriekš norādīto attēlu?

 

Ceru ka sapratāt un paldies jau iepriekš

 

P.s.

 

Upload.php fails:

<?
foreach ($_FILES["images"]["error"] as $key => $error) {
  if ($error == UPLOAD_ERR_OK) {
    $name = $_FILES["images"]["name"][$key];
    move_uploaded_file( $_FILES["images"]["tmp_name"][$key], "uploads/" . $_FILES['images']['name'][$key]);
    print "uploads/" . $_FILES['images']['name'][$key] . "<br>";
  }
}
?>
Edited by sandrulis
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