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Uztaisīju šādi:

$test = mysql_query("SELECT phpbb_profile_fields_data.pf_ingame_nick FROM CooMFP.phpbb_profile_fields_data phpbb_profile_fields_data INNER JOIN psychostatszmwar.ps_plr_ids_name ps_plr_ids_name ON phpbb_profile_fields_data.pf_ingame_nick = ps_plr_ids_name.name");


print_r($test);

Bet rezultāts ir

Resource id #5

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