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Posted (edited)

Izveidoju pavisam vienkāršu lapu dalīšanas sistēmu: Iepriekšējā Nākošā lapa.

 

Tākā no cikliem neko nesaprotu man ir jautājums, kā lai izveido tā, lai rādīt visas nākamās un iepriekšējās lapas. Lai būtu "Iepriekšējā 4 5 6 7 8 9 Nākamā".

 

Tagadējais kods

 

if(isset($_GET['page']) && ctype_digit($_GET['page'])){
$page = $_GET['page'];
}else{
$page = 1;
}

$inonepage = 3;

$start_from = ($page*$inonepage) - $inonepage;


$sql = mysql_query("SELECT * FROM news ORDER BY id DESC LIMIT $start_from,$inonepage");
while($row = mysql_fetch_array($sql)){
//saturs
}
$pageback = $page-1;
if($page > 1){
echo '<a href="?page='.$pageback.'">Atpakaļ</a>';
}

echo $page;

$countrows = mysql_num_rows(mysql_query("SELECT * FROM news"));
if($countrows > ($page*$inonepage) - $inonepage + $inonepage){
$pagenext = $page+1;
echo '<a href="?page='.$pagenext.'">Nākošā</a>';
}

}

 

Jau iepriekš paldies

Edited by forSilence
Posted
function draw_pages($count, $perpage, $offset = 5) {
$pages = ceil($count/$perpage);
if($pages < 2) return '';
$r = '<br />';
$page = (empty($_GET['p']) || $_GET['p'] < 2) ? 1 : (int)$_GET['p'];
$first = $page >= $offset+1 ? $page-$offset : 1;
$last = $page <= $pages-$offset ? $page+$offset : $pages;
if($page > 4) $r.= sprintf('?p=1">«</a><a href="?p=%d"><</a>', $page-1);
for($i = $first; $i <= $last; $i++) $r.= sprintf('%s<a href="?p=%d" style="color: white;background: green;border: 3px solid #eaeaea; padding: 3px; float: left;">%d</a>', $page==$i ? '' : '', $i, $i);
if($pages > 4) $r.= sprintf('<a href="?p=%d">></a><a href="?p=%d">»</a>', $page+1, $pages);
return '<div class="down_pager">'.$r.'</div>';
}

Posted

$countrows = mysql_num_rows(mysql_query("SELECT * FROM news"));

Šitā darīt nebūtu īsti prātīgi.

Tā vietā var izmantot

 

$sql = mysql_query("SELECT SQL_CALC_FOUND_ROWS * FROM news ORDER BY id DESC LIMIT $start_from,$inonepage");
....
$result = mysql_query("SELECT FOUND_ROWS()");
$countrows = mysql_result($result,0);

Posted

SQL_CALC_FOUND_ROWS diezgan smagi bremzē, salīdzinot ar COUNT(*), taču ir krietni parocīgāks, ja ieraksti atlasīšanai izmanto WHERE, GROUP BY, utt nosacījumus.

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