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function exptolvl($exp){

if ($exp > 10) {

return ($exp/100)*10;

} else {

return 0;

}

}

 

Esmu visu aizmirsis, ak dievs... Nepieciešama formula kas atgriež līmeņus.

 

1lv = 10

2lv = 20

3lv = 40

4lv = 80

5lv = 160

utt..

Es zinu ka tas ir stulbi, bet nevaru jau 30 minūtes iebraukti.

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function exp2lvl($e){
 if ($e<10) return 0;
 return floor(log($e/10,2))+1;
}
for ($i=1;$i<=100;$i++){
 echo $i.' '.exp2lvl($i).'<br />';
}

 

 

2easystyle:

function e2l($e){return $e<10?0:floor(log(($e/10),2))+1;}

Edited by codez
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codez, varbūt būsi tik laipns un samazināsi arī šis rindas :D

 

	function exptoprocents($e){
		if ($e>=640) { return percent($e-640,640); }
	elseif ($e>=320) { return percent($e-320,320); }
		elseif ($e>=160) { return percent($e-160,160); }
		elseif ($e>=80) { return percent($e-80,80); }
		elseif ($e>=40) { return percent($e-40,40); }
		elseif ($e>=20) { return percent($e-20,20); }
	elseif ($e>=10) { return percent($e-10,10); }
		else { return $e; }
}

function percent($num_amount, $num_total) {
	$count1 = $num_amount / $num_total;
	$count2 = $count1 * 100;
	$count = number_format($count2, 0);
	return $count;
}

 

Atgriež procentos, cik līdz nākamajam līmenim palicis.

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function e2l($e){return $e<10?0:floor(log(($e/10),2))+1;}
function l2e($l){return $l<1?0:pow(2,$l-1)*10;}
function nl($e){return ($e-($e1=l2e($l=e2l($e))))/(l2e($l+1)-$e1)*100;}
for ($i=1;$i<=100;$i++){
 echo $i.' '.e2l($i).' '.nl($i).'%<br />';
}

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