gkazhus

if ( !in_array($GLOBALS['pagenow'], array('wp-login.php', 'wp-register.php' )) && !is_admin() && !is_user_logged_in() ) { wp_redirect('/wp-login.php', 301); exit; } Vai kaads luudzu var pateikt kur sheit man ir kluuda, jo atverot wp-register.php lapu ta tiek automatiski parmesta uz wp-login.php lapu lai gan esmu tacu pielicis, ka taa netiek redirektota. Ka es varu to izlabot?

Tik kaa Wordpresaa dabuut aaraa username?

Man ir nepiecieshamiiba izveidojot jaunu Menu linku lai shis links aizvestu uz piem. /users/USERNAME/ Vai arii ja tas ir izdarams varbut to var izdariit DB?

Taatad meeginu izveidot lai man bildes nosaukums buutu taads pats kaa virsraksts - item-title bet taa vietaa es sanjemu shaadu izvadu: <img src="/uploads/Egles" ciekurs.jpg"="" class="image" alt="" style="background-color: rgb(245, 111, 20); width: 160px; height: 160px; display: block;" data-lazy-loaded="true"> Kaa lai es sho - Egles" ciekurs.jpg parversu Egles ciekurs.jpg Kods: $image='<img src="/uploads/'.$arr['item-title'].'.jpg" class="image" alt="" style="'.$image_style.$item_style.' width: '.$w.'px; height: '.$h.'px;" />';

ok tnx.. tagad palika skaidraaka taa lieta ;)

Mekleju padomu - Ka uztaisiit profilam ta lai cits lietotajs varetu "piemiegt ar aci" vai wink. Un pec tam tas butu redzams ka kads Tev ir piemiedzis...

ok done tnx ;)

Kaa lai pareizi pieraksta preg_match nosacijumus: šobrid sanjemu error Warning : preg_match() [ function.preg-match ]: Delimiter must not be alphanumeric or backslash $OSList = array ( // Match user agent string with operating systems 'Windows 3.11' => 'Win16', 'Windows 95' => '(Windows 95)|(Win95)|(Windows_95)', 'Windows 98' => '(Windows 98)|(Win98)', 'Windows 2000' => '(Windows NT 5.0)|(Windows 2000)', 'Windows XP' => '(Windows NT 5.1)|(Windows XP)', 'Windows Server 2003' => '(Windows NT 5.2)', 'Windows Vista' => '(Window

Vai sheit ir kaads kursh gribetu uznjemties sho darbu?

Kursh prastu savienot Drupal ar maksaajuma sistemu. Ir nepiecieshams uzlikt maksaajuma sistemu lai lietotajs ar sms vai bankas parskaitijumu varetu upgreidot savu profilu piem. uz meenesi.

Kas iisti tur nav pareizi?

Man ir probleema ar filtresanas php. Man ir dropdown menu kuraa ir ,manaa gadiijumaa memberi. Bet izveeloties attieciigo memberi neatrod siikaakas detaljas par vinju <?php /* Include Files *********************/ //include("banners/database.php"); mysql_connect("hosts", "user", "pwd") or die("Connection Failed"); mysql_select_db("DB")or die("Connection Failed"); ?> <?php if (isset($_POST["memberIndustries"])) { $memberIndustries = mysql_real_escape_string ($_POST["memberIndustries"]); $sqlQuery = "SELECT * FROM Members WHERE member= "$memberIndustries""; $result = mysql_que

t izvada tekstu Next. Karoče man ir links Next, bet tā vietā gribu dabūt bultiņas bildi uz kuras uzkliķšinot pāriet uz nākamo lapu.

<td class="image-navigator-next"> <?php print isset($next_link) ? '<a href="'. $next_link .'"><img scr="/sites/all/modules/node_gallery/theme/arrow.png">'. t('Next') .' </a>' : ' '; ?> </td> Kaa lai shajaa kodaa iedabuuju bildi pareizi?

Kas sheit ir netaa? function update(i) { createRequest(); var params="id="+i; params=params+"&ac=3"; params=params+"&newUrl="+document.getElementById(i).value; params=params+"&DATEFROM="+document.getElementById(i).value; params=params+"&DATETO="+document.getElementById(i).value; //alert(params); request.open("POST", "/banners/ajax.php", false); request.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); request.onreadystatechange = updatePage; request.send(params); }