So sick!

IE ir developer fīča (F12) ar kuru var 'pārslēgties' visās IE versijās līdz IE6.

Ar html5 domāts <header>, <section>, <footer>.

Iesāku kodēt vienai lapai frontendu uz html5, bet kad iegāju ar veco IE, tad visa lapa bija neglīta. Kā man labāk darīt: 1) pārkodēt visu uz html vai 2) turpināt uz html5, jo .... ?

Ls 50-100

Nepieciešams mājaslapu dizaineris viena portāla re-design. Kontakti: Skype: braaleeni Epasts: [email protected]

Drīkst visu, tik vai vajag?

Tev iedeva to, ko tu gribēji, tik bez bildēm. ;)

Ar jquery vienkārši pie close f-jas pieliec, lai uzreiz atver jaunu popupu un izvelk random bildi.

Izmanto cookie ;)

window.open ;)

Pie bilžu saglabāšanas izmanto strtolower($fails).

Strādā, bet nu.. kā jau teici, šausmas.. :D

Šo fīču taisīju vienam interneta veikalam, taču, tas interneta veikals vairs nepastāv un tāpēc izdomāju publicēt šo skriptiņu.. nekas liels, bet nu.. gatavs skriptiņš :) <?php header("Content-type: text/xml"); // Settings $website = 'veikals.lv'; // Connection $link = mysql_connect("localhost", "user", "parole"); $select_db = mysql_select_db("opencart"); // Select $sql = "SELECT product_description.name, product.product_id, product.price, product.image, category.parent_id, product_to_category.category_id FROM product LEFT JOIN product_description ON product.product_id=product_description.product_id LEFT JOIN product_to_category ON product.product_id=product_to_category.product_id LEFT JOIN category_description ON product_to_category.category_id=category_description.category_id LEFT JOIN category ON category.category_id=category_description.category_id"; $result = mysql_query($sql) or die (mysql_error()); $xml_output = "<?xml version=\"1.0\" encoding=\"utf-8\"?>\n"; $xml_output .= "<root>\n"; $prev_value = 0; while ($line = mysql_fetch_assoc($result)) { if ($prev_value != $line['product_id']) { $prev_value = $line['product_id']; // Echo $parent_id = $line['parent_id']; $sql2 = "SELECT name FROM category_description WHERE category_id=$parent_id AND language_id=2"; $result2 = mysql_query($sql2) or die (mysql_error()); while($parent_name1 = mysql_fetch_assoc($result2)){ $parent_name = $parent_name1['name']; } if(isset($parent_name)) {$parent_symbol = ">";}else{$parent_symbol = "";} $category_id = $line['category_id']; $sql3 = "SELECT name FROM category_description WHERE category_id=$category_id AND language_id=2"; $result3 = mysql_query($sql3) or die (mysql_error()); while($category_name1 = mysql_fetch_assoc($result3)){ $category_name = $category_name1['name']; } $xml_output .= "<item>\n"; $xml_output .= "<name>".$line['name']."</name>\n"; $xml_output .= "<link>http:///".$website."/index.php?route=product/product&product_id=".$line['product_id']."</link>\n"; $xml_output .= "<price>".$line['price']."</price>\n"; $xml_output .= "<image>http://".$website.".lv/image/".$line['image']."</image>\n"; $xml_output .= "<category>".$category_name."</category>\n"; $xml_output .= "<category_full>".$parent_name." ".$parent_symbol." ".$category_name."</category_full>\n"; $xml_output .= "<category_link>http:///".$website."/index.php?route=product/category&path=".$line['category_id']."</category_link>\n"; $xml_output .= "</item>\n"; } } $xml_output .= "</root>"; echo $xml_output; ?> P.s. Vajadzētu strādāt perfekti uz kurpirkt.lv un salidzini.lv P.p.s. Last modified 15.03.2011 :D

OS = Operētājsistēma O/S = Open Source ;) Bet nu lai veicās :D

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