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ziedinjsh

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Posts posted by ziedinjsh

  1. es jau štukoju.. mošk kodā nav kaut kas vai arī ar seozām :?

    <?php
    
    $status = (isset($_GET['status'])) ? $_GET['status'] : '';
    
    if(isset($_POST['login'])){
    
    $email = strip_tags($_POST['email']);
    $password = strip_tags($_POST['password']);
    
    $query = sprintf("SELECT ID FROM users WHERE email = '%s' AND password =  '%s' LIMIT 1;", mysql_real_escape_string($email), md5($password));
    $result = mysql_query($query) or die(mysql_error);
    if(mysql_num_rows($result) != 1){ 
    
    echo "<span style='color:#ff0000'>bad login</span>";
    
    }else{
    $row = mysql_fetch_assoc($result);
    
    $_SESSION['user_ID'] = $row['ID'];
    
    }
    }
    
    echo "<form method='post' action='".$_SERVER['PHP_SELF']."'>";
    echo "<table><tr>";
    echo "<td>email</td><td><input type='text' name='email'></td>";
    echo "</tr><tr>";
    echo "<td>password</td><td><input type='password' name='password'></td>";
    echo "</tr><tr>";
    echo "<td></td><td><input type='submit' name='login' value='Login'></td>";
    echo "</tr><tr>";
    echo "<td><a href='register.php'>Register?</a></td><td><a href='lost.php'>Lost password?</a></td>";
    echo "</tr></table>";
    
    
    ?>
    

  2. nu ok.. tagadir šādi

    <?php
    include "misc/config.php";
    include "header.php";
    include "left.php";
    
    
    
    $result = mysql_query("SELECT * FROM users ORDER BY id DESC");
    while($data = mysql_fetch_array($result))
    {
    
    if(isset ($_GET['id']))
    {
    $id = $_GET['id'];
    
    $query= mysql_query("delete FROM users where id =$id")or die(mysql_error());
    }
    
    
    
    
    echo "<form method='post' action='".$_SERVER['PHP_SELF']."'>";
    echo "<table><tr>";
    echo "<td>username</td><td>".$data['username']."</td>";
    echo "</tr><tr>";
    echo "<td>email</td><td>".$data['email']."</td>";
    echo "</tr></table>";
    echo "".$data['id']."";
    echo "<a href='users.php?page=delete&id=".$data['id']."'>delete user</a>";
    echo "</form>";
    echo "<hr>";
    
    }
    
    
    include "footer.php";
    ?>
    

     

    kods strādā, bet tikai ja spiez uz linka 2x.. vienreiz nospiež nekas nenotiek.. pārlādējas tikai lapa, bet kad nospiež otro reizi tad izdzēš.. kapēc tā?

  3. nesaprotu kapēc rāda šadu notici:

    Notice: Undefined index: users in /home/produc/public_html/mp3/1/admin/users.php on line 12

     

    Notice: Use of undefined constant delete - assumed 'delete' in /home/produc/public_html/mp3/1/admin/users.php on line 12

     

    users.php:

    <?php
    include "misc/config.php";
    include "header.php";
    include "left.php";
    
    $result = mysql_query("SELECT * FROM users ORDER BY id DESC");
    while($data = mysql_fetch_array($result))
     {
    
    
    
    if($_GET["users"]==delete)
    {
       $sql = "DELETE FROM users WHERE id=$id";
       $result = mysql_query($sql);
       echo "User deleted!";
    }
    
    
    echo "<form method='post' action='index.php?page=users'>";
    echo "<table><tr>";
    echo "<td>username</td><td>".$data['username']."</td>";
    echo "</tr><tr>";
    echo "<td>email</td><td>".$data['email']."</td>";
    echo "</tr></table>";
    echo "".$data['id']."";
    echo "<a href='users.php?page=delete&id=".$data['id']."'>delete user</a>";
    echo "</form>";
    echo "<hr>";
    }
    
    
    
    include "footer.php";
    ?>
    

     

    kapēc rodas šāda notice un kapēc nedzēš?

  4. jā tikoes arī par to aizdomājos.. pieliku session_start(); un aizgāja

     

    Paldies! :)

     

    uztaisīju logout.php bet bet kad meoģinu izlogoties parāda šādu Warning: session_destroy() [function.session-destroy]: Trying to destroy uninitialized session in /home/produc/public_html/mp3/1/logout.php on line 2

     

    Warning: Cannot modify header information - headers already sent by (output started at /home/produc/public_html/mp3/1/logout.php:2) in /home/produc/public_html/mp3/1/logout.php on line 3

     

    logout.php:

    <?php
    session_destroy();
    header("Location:index.php");
    ?>
    

    betman liekas, ka kkas trūkst :D

     

    un kāds varētu izskatīties kods kurš atpazīst vai ir ielogojies vai nē.. piem man ir šādi:

    <div id='left'>
    include "login.php";
    
    include "profile.php";
    
    </div>
    

    protams, ka rādīsies abi divi, bet kā varētu panāk sādu efektu:

    <div id='left'>
    
    if(member){
    include "profile.php";
    }else{
    include "login.php";
    }
    

  5. login.php

    <?php
    session_start();
    include "misc/config.php";
    $status = (isset($_GET['status'])) ? $_GET['status'] : '';
    
    if(isset($_POST['login'])){
    
    $email = strip_tags($_POST['email']);
    $password = strip_tags($_POST['password']);
    
    $query = sprintf("SELECT ID FROM users WHERE email = '%s' AND password =  '%s' LIMIT 1;", mysql_real_escape_string($email), md5($password));
    $result = mysql_query($query) or die(mysql_error);
    if(mysql_num_rows($result) != 1){ 
    
    header('Location: login.php?status=error');
    }else{
    $row = mysql_fetch_assoc($result);
    
    $_SESSION['user_ID'] = $row['ID'];
    header('Location: profile.php');
    }
    }
    if ($status == 'error'){
    echo "<span style='color:#ff0000'>bad login</span>";
    }
    echo "<form method='post' action='".$_SERVER['PHP_SELF']."'>";
    echo "<table><tr>";
    echo "<td>email</td><td><input type='text' name='email'></td>";
    echo "</tr><tr>";
    echo "<td>password</td><td><input type='password' name='password'></td>";
    echo "</tr><tr>";
    echo "<td></td><td><input type='submit' name='login' value='Login'>";
    echo "</tr></table>";
    ?>
    

     

    tātad sanāk ka vajadzētu izskatīties šadi:

    $_SESSION['user_ID']
    

     

    jo iekš login.php ir šādi:

    $_SESSION['user_ID'] = $row['ID'];
    

     

    Šādi man izskatās profiles.php:

    <?php
    
    include "misc/config.php";
    
    
    
    
    $result = mysql_query("SELECT * FROM users WHERE username= '{$_SESSION['user_ID']}'");
    
    
    
    while($data = mysql_fetch_array($result))
     {
    
    
    
    echo "<table><tr>";
    echo "<td>username</td><td>".$data['username']."</td>";
    echo "</tr><tr>";
    echo "<td>email</td><td>".$data['email']."</td>";
    echo "</tr></table>";
    echo "".$data['id']."";
    echo "<hr>";
    }
    
    
    
    ?>
    

    ielogojoties man parādās tukša lapa

  6. Paldies waplet, aizgāja, bet kā tagad, lai es izdaru tā:

     

    ielogojoties man aizmet uz lapu profiles.. tur parādās visi reģistrētie profili, bet kas man jādara lau parādītos tikai tas profils kurā es ielogojos un darbības notiktu tikai ar to profilu.. nu kā lietotājam kurš ir ielogojies?

     

    profiles.php:

    <?php
    include "misc/config.php";
    
    
    
    
    $result = mysql_query("SELECT * FROM users ORDER BY id DESC");
    while($data = mysql_fetch_array($result))
     {
    
    
    
    echo "<table><tr>";
    echo "<td>username</td><td>".$data['username']."</td>";
    echo "</tr><tr>";
    echo "<td>email</td><td>".$data['email']."</td>";
    echo "</tr></table>";
    echo "".$data['id']."";
    echo "<hr>";
    }
    
    
    
    ?>
    

     

    kā varētru izveidot kko šādu:

    if (member) {
    echo "te rādās viskautkas tike prekš reģistrētiem";
    }
    else {
    echo "viesiem";
    }
    
    //viesiem
    
    if (guest){
    echo "kkas viesiem tikai, ko neredz reģistreeti";
    }
    

  7. Sveiki!

     

    Šāds ir reģistrēšanas kods:

    <?php
    include "misc/config.php";
    
    $submit = $_POST['register'];
    //Savāc datus
    $username =  strip_tags($_POST['username']);
    $email = strip_tags($_POST['email']);
    $password = strip_tags($_POST['password']);
    $password2 = strip_tags($_POST['password2']);
    $date = date("y-m-d");
    
    
      if ($submit)
    {
    
      //Paarbauda vai nav tuksh
      if($username&&$email&&$password&&$password2)
    {
    
      if($password==$password2)
      {
    
      //parbaudiis useranme un email garumu
      if(strlen($username)>50||strlen($email)>50)
      {
       echo "Lenght of username or/and email is too long!";
      }
      else
      {
    
      //paarbauda password garumu
      if (strlen($password)>20||strlen($password)<6)
      {
       echo "Password must be between 6 and 20 characters!";
      }
      else
      {
       //Registreet lietotaaju
    
        // nokodee password ar md5
        $password = md5($password);
        $password2 = md5($password);
    
       $query = mysql_query("INSERT INTO users VALUES ('','$username','$email','$password','$date') ");
    
       die("You hav been registred!");
    
      }
    
      }
    
      }
       else
       	echo "Your password do not match!";
    
    }
    else
    echo "Please fill all feilds!";
    
    }
    ///
    
    echo "<form method='post' action='".$_SERVER['PHP_SELF']."'>";
    echo "<table>";
    echo "<tr>";
    echo "<td>username</td><td><input type='text' name='username' value='$username'></td>";
    echo "</tr><tr>";
    echo "<td>email</td><td><input type='email' name='email' value='$email'></td>";
    echo "</tr><tr>";
    echo "<td>password</td><td><input type='password' name='password'></td>";
    echo "</tr><tr>";
    echo "<td>password2</td><td><input type='password' name='password2'></td>";
    echo "</tr><tr>";
    echo "<td></td><td><input type='submit' name='register' value='register'></td>";
    echo "</tr>";
    echo "</table>";
    echo "</form>";
    ?>
    

    Kods strādā.. datus ievada iekš mysql.. izvadot datus viss parādās..

     

    Es nevaru ielogotes!!

    šāds ir ielogošanās kods:

    <?php
    session_start();
    include "misc/config.php";
    $status = (isset($_GET['status'])) ? $_GET['status'] : '';
    
    if(isset($_POST['login'])){
    
    $email = strip_tags($_POST['email']);
    $password = strip_tags($_POST['password']);
    
    $query = sprintf("SELECT ID FROM users WHERE email = '$email' AND password = '$password' LIMIT 1;", mysql_real_escape_string($email), md5($password));
    $result = mysql_query($query) or die(mysql_error);
    if(mysql_num_rows($result) != 1){ 
    
    header('Location: login.php?status=error');
    }else{
    $row = mysql_fetch_assoc($result);
    
    $_SESSION['user_ID'] = $row['ID'];
    header('Location: login.php?status=done');
    }
    }
    if ($status == 'error'){
    echo "<span style='color:#ff0000'>bad login</span>";
    }
    echo "<form method='post' action='".$_SERVER['PHP_SELF']."'>";
    echo "<table><tr>";
    echo "<td>email</td><td><input type='text' name='email'></td>";
    echo "</tr><tr>";
    echo "<td>password</td><td><input type='password' name='password'></td>";
    echo "</tr><tr>";
    echo "<td></td><td><input type='submit' name='login' value='Login'>";
    echo "</tr></table>";
    
    
    if($status == 'done'){
    echo "Welcome to member eare";
    }
    
    
    
    
    ?>
    

     

    Kas man nav pareizi? vai kāds lūdzu nevarētu izlabot vai pielabot?

  8. Šāds ir kods:

    <?php
    error_reporting(E_ALL);
    include "misc/config.php";
    
    
    
    if (isset($_POST['get_photo'])) {
    
    
    // faila detaljas
    $p_name = $_FILES["photo"]["name"];
    $p_type = $_FILES["photo"]["type"];
    $p_size = $_FILES["photo"]["size"];
    $p_temp = $_FILES["photo"]["tmp_name"];
    $p_error = $_FILES["photo"]["error"];
    $p_date = date("Y-m-d");
    $p_time = time("H:i:s");
    
    
    if($p_error > 0)
      die ("photo culd not uploaded! Code: $p_error");
    
     else {
    
     //Faila nosaciijumi
       if($p_type == "application/octet-stream" || $p_size >3145728) {
     die("this format is not allowed or file is to big");
    
     }
     else
     {
    
    $query = mysql_query("INSERT INTO photos (p_name, p_type, p_size, p_date, p_time) VALUES ('$p_name','$p_type','$p_size','$p_date', 'p_time') ");
     move_uploaded_file($p_temp,"uploads/".$p_name);
      echo "photo uploaded!";
      }
    }	
    
    
    
    
    }
    echo "<form method='post' action='".$_SERVER['PHP_SELF']."' enctype='multipart/form-data'>";
    echo "<input type='file' name='photo'>";
    echo "<input type='submit' value='Upload' name='get_photo'>";
    echo "</form>";
    
    ?>
    

    viņš augšupielādē bildi iek uploads foldera.. un ieliek datus iekš mysql.

     

    Tātad.. Kā varētu uztaisīt tā kad augšupielādējas bilde un arī taj pašai bildei izveidojas thumbnail iekš uploads/small

  9. Sveiki.

     

    Šādi izskatās kods:

    <?php
    include "misc/config.php";
    if (isset($_POST['get_photo'])) {
    
    // faila detaljas
    $p_name = $_FILES["photo"]["name"];
    $p_type = $_FILES["photo"]["type"];
    $p_size = $_FILES["photo"]["size"];
    $p_temp = $_FILES["photo"]["tmp_name"];
    $p_error = $_FILES["photo"]["error"];
    $p_date = date("y-m-d");
    
    if($p_error > 0)
      die ("photo culd not uploaded! Code: $p_error");
    
     else {
    
     //Faila nosaciijumi
     if($p_type == "application/octet-stream" || $p_size >3145728) {
     die("this format is not allowed or file is to big");
     }
     else
     {
    
    $query = mysql_query("INSERT INTO photos (p_name, p_type, p_size, p_date) VALUES ('','$p_name','$p_type','$p_size','$p_date') ");
     move_uploaded_file($p_temp,"uploads/".$p_name);
      echo "photo uploaded!";
      }
    }	
    
    
    
    
    
    
    
    }
    echo "<form method='post' action='".$_SERVER['PHP_SELFE']."' enctype='multipart/form-data'>";
    echo "<input type='file' name='photo'>";
    echo "<input type='submit' value='Upload' name='get_photo'>";
    echo "</form>";
    ?>
    

     

    failu viņš augšupielādē, bet informāciju datubāzē neieliek.. kas nav pareizi?

     

    kur man jālike md5(); funkcija lai augšupielādējot faili viņš būtu nokodēts ar md5(); un paliktu faila formāts?

     

    meiģināju šādi:

    $p_name = md5($_FILES["photo"]["name"]);
    

    failu viņš nokodēja ar md5 bet fomāts galā nebija

     

    varbūt ir kāds gatavs kods kur datus ieliek mysql un var augšupielādēt tikai bilžu failus ar md5(); funkciju?

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