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didy

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Posts posted by didy

  1. <?
    require ($_SERVER["DOCUMENT_ROOT"]."/config/db_config.php");
    $connection = @mysql_connect($db_host, $db_user, $db_password); 
    if (!$connection)
    {
    die ('Could not connect: ' . mysql_error());
    }
    mysql_select_db("latbit_db", $connection);
    
    $query  = "SELECT id, name FROM upload";
    $result = mysql_query($query) or die('Error, query failed');
    if(mysql_num_rows($result) == 0)
    {
    echo "Database is empty <br>";
    } 
    else
    {
    while(list($id, $name) = mysql_fetch_array($result))
    {
    ?>
    	<img src="index.php?id=<?=$id;?>"/><br>
    <?php
    }
    }
    mysql_close($connection);
    ?>

    un

    <?php
    
    require ($_SERVER["DOCUMENT_ROOT"]."/config/db_config.php");
    $connection = @mysql_connect($db_host, $db_user, $db_password); 
    if (!$connection)
    {
    die ('Could not connect: ' . mysql_error());
    }
    mysql_select_db("latbit_db", $connection);
    
    $result = mysql_query("SELECT * FROM upload_txt");
    
    echo "<table border='1'>
    <tr>
    <th>id</th>
    <th>title</th>
    <th>description</th>
    </tr>";
    
    while($row = mysql_fetch_array($result))
     {
     echo "<tr>";
     echo "<td>" . $row['autoID'] . "</td>";
     echo "<td>" . $row['title'] . "</td>";
     echo "<td>" . $row['description'] . "</td>";
     echo "</tr>";
     }
    echo "</table>";
    
    mysql_close($connection);
    ?>

    Ka lie apvienoju sos divus skriptus? Neko daudz no php nezinu, tapec busu pateiciigs ja izkaidrotu cilveciski. ja pareizi domaju ta man vajag apvienot

    while(list($id, $name) = mysql_fetch_array($result))

    ar

    while($row = mysql_fetch_array($result))

  2. Warning: fopen(image/png) [function.fopen]: failed to open stream: No such file or directory in E:\webroot\uploader.php on line 23

     

    Warning: fread(): supplied argument is not a valid stream resource in E:\webroot\uploader.php on line 23

    Field 'name' doesn't have a default value

     

    "No such file or directory" direktorija ir!

  3. <?php
    // failu parbaude (extensiju parbaude + max lielums
    if 
    ((($_FILES["file"]["type"] == "image/gif")
    || ($_FILES["file"]["type"] == "image/jpeg")
    || ($_FILES["file"]["type"] == "image/jpg")
    || ($_FILES["file"]["type"] == "image/png")
    || ($_FILES["file"]["type"] == "image/pjpeg"))
    && ($_FILES["file"]["size"] < 20000))
    {
     // Pievienosanas DB
      require ($_SERVER["DOCUMENT_ROOT"]."/config/db_config.php");
      $connection = @mysql_connect($db_host, $db_user, $db_password) or die ("error connecting");
      mysql_select_db($db_name, $connection);
    
    	  $data = addslashes(fread(fopen($_FILES["file"]["type"], "r"), $_FILES["file"]["size"]));
    
    			 // Faila ievietosana tabula
    		$query = mysql_query("INSERT INTO upload_img (file) VALUES ('$data')") 
    		or die("Can't Perform Query");
    		mysql_query($query, $connection) or die (mysql_error());
    
    		// Augsupladeta faila info (nosaukums, lielums)
    echo "Upload: " . $_FILES["file"]["name"] . "<br />";
    echo "Size: " . ($_FILES["file"]["size"]) . " Kb<br />";
    }
    // Ja vails neatbilst (izvada else)
    else {echo "Nepareizs fails";}
    ?>

     

     

    Warning: fopen(image/png) [function.fopen]: failed to open stream: No such file or directory in E:\webroot\uploader.php on line 23

     

    Warning: fread(): supplied argument is not a valid stream resource in E:\webroot\uploader.php on line 23

    Can't Perform Query

     

    DB izveidoju tabulu upload_img

     

     CREATE TABLE `latbit_db`.`upload_img` (
    `autoID` INT( 64 ) UNSIGNED NOT NULL AUTO_INCREMENT ,
    `name` VARCHAR( 64 ) NOT NULL ,
    `size` INT NOT NULL ,
    `type` VARCHAR( 64 ) NOT NULL ,
    `file` BLOB NOT NULL ,
    PRIMARY KEY ( `autoID` )
    ) ENGINE = InnoDB

     

    Kur kluda?

  4. piemetu:

    mysql_query($query, $connection) or die (mysql_error());

     

    ERROR:

     

    You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1

  5. <?php
    
    if ((($_FILES["file"]["type"] == "image/gif")
    || ($_FILES["file"]["type"] == "image/jpeg")
    || ($_FILES["file"]["type"] == "image/jpg")
    || ($_FILES["file"]["type"] == "image/png")
    || ($_FILES["file"]["type"] == "image/pjpeg"))
    && ($_FILES["file"]["size"] < 20000))
     {
     if ($_FILES["file"]["error"] > 0)
    {
    echo "Error: " . $_FILES["file"]["error"] . "<br />";
    $mysqlp = addslashes(fread(fopen($_FILES["file"]["type"], "r"), $_FILES["file"]["size"]));
    }
     else
    {
    
      require ($_SERVER["DOCUMENT_ROOT"]."/folder/configs.php");
      $connection = @mysql_connect($db_host, $db_user, $db_password) or die ("error connecting");
      mysql_select_db($db_name, $connection);
    if (isset($_POST['mysqlp'])){
    		  mysql_query("INSERT INTO img_upload (Image) VALUES ('$mysqlp')") or die("Can't Perform Query");
    }
    echo "Upload: " . $_FILES["file"]["name"] . "<br />";
    echo "Stored in: " . $_FILES["file"]["tmp_name"] . "<br /><br />";
    }
     }
    else
     {
     echo "Invalid file";
     }
    
    ?>

     

    Samonteju sadu skriptinu. Itka nekadas kludas neuzrada, bet DB nesaglabajas! KO izdariju nepareizi?

  6. If($Picture != "none") {

    $PSize = filesize($Picture);

    $mysqlPicture = addslashes(fread(fopen($Picture, "r"), $PSize));

     

    nomainot $Picture mainigo uz $_FILES['Picture'] - reakcija nekada!

  7. <?php
    
    if (isset($_FILES['Picture']))
    {
    If($Picture != "none") {
    $PSize = filesize($Picture);
    $mysqlPicture = addslashes(fread(fopen($Picture, "r"), $PSize));
    }
    require ($_SERVER["DOCUMENT_ROOT"]."/folder/configs.php");
    $connection = @mysql_connect($db_host, $db_user, $db_password) or die ("error connecting");
    mysql_select_db($db_name, $connection);
    
    mysql_query("INSERT INTO img_upload (Image) VALUES ('$mysqlPicture')") or die("Can't Perform Query");
    }
    else {
    echo"You did not upload any picture";
    }
    ?>

     

    Joprojam neka! Izmet joprojam else - "You did not upload any picture"

     

    Kluda "equire ($_SERVER["DOCUMENT_ROOT"]."/folder/configs.php");" nebus vainiga, ka ari "upload.php" Man nikis pirms postesanas nomainit foldera un lapas nosaukumu! Nejauta kadeel!

     

    Man vaig uploudu ar DB! Meklesu vel!

  8. <form enctype="multipart/form-data" action=" upload.php" method="POST">
    <input type="hidden" name="MAX_FILE_SIZE" value="250000" />
    Send this file: <input name="Picture" type="file" />
    <input type="submit" value="Send File" />
    </form>

     

     

    if (isset($Picture))
    {
    If($Picture != "none") {
    $PSize = filesize($Picture);
    $mysqlPicture = addslashes(fread(fopen($Picture, "r"), $PSize));
    }
    require ($_SERVER["DOCUMENT_ROOT"]."/fold/configs.php");
    $connection = @mysql_connect($db_host, $db_user, $db_password) or die ("error connecting");
    mysql_select_db($db_name, $connection);
    
    mysql_query("INSERT INTO img_upload (Image) VALUES ('$mysqlPicture')") or die("Can't Perform Query");
    }
    else {
    echo"You did not upload any picture";
    }
    ?>

     

    Kadel nesanak augsupladet datubaze ? Ko esmu nepareizi izdarijis?

    izvada man else - "You did not upload any picture"

  9. Ir izveidots upload kodins. Augsupladejot bildi vina saglabajas noteiktaja mape!

    Jautajum: Ka lai izveidoju lai augsupledaatais fails saglabaajas un nopostojas weba!

     

     

    edit:

    PS. atradu info! Paldies, tiksu gala!

  10. Foruma vieta varetu ielikt saiti uz php.net un google.lv un varbuut uz wiki! Tas pats vien butu! Vareji jau njemt vera kad teicu

    "nevareju isti saprast ka parbaudiit ar isset vai empty"

    Meginaju ka paradiits isset() - nekada rezultata! Tadel jau nacu uz forumu pec palidzibas! Bet paldies! Gan jau tiku gala!

  11. <?php
    require ($_SERVER["DOCUMENT_ROOT"]."/folder/config.php");
    $connection = @mysql_connect($db_host, $db_user, $db_password) or die ("error connecting");
    mysql_select_db($db_name, $connection);
    
    $name = $_POST["txt_name"];
    $len = strlen ($name);
    //Only write to database if there's a name
    if ($len > 0)
    {
    	$email = $_POST["txt_email"];
    	$comment = $_POST["txt_comment"];
    	$date = time();
    
    	$query = "INSERT INTO guestbook (autoID, name, email, comment, date_auto) VALUES (NULL, '$name', '$email', '$comment', '$date')";
    	mysql_query($query, $connection) or die (mysql_error());
    }
    ?>

     

    Problema: Notice: Undefined index: txt_name in E:\webroot\guestbook.php on line 5

    ($name = $_POST["txt_name"];)

     

    kur kluda?

  12. OS: WinXP

    Uzstadiju: Apache2.2.8, php5.2, mysql 5.0

    Problema: nevaru piesaistiit mysql db

     

    parbaude - ieks index.php

     

    <?php
    $link = mysql_connect('localhost', 'lietotajvards', 'manaparole');
    if (!$link) {
      die('Could not connect: ' . mysql_error());
    }
    echo 'Connected successfully';
    mysql_close($link);
    ?>

     

    Izmet man:

    Fatal error: Call to undefined function mysql_connect() in E:\folderis\index.php on line 8

     

    meginaju citu variantu:

     

    <?
    require ($_SERVER["DOCUMENT_ROOT"]."/config/db_config.php");
    $connection = @mysql_connect($db_host, $db_user, $db_password) or die ("error connecting");
    echo "connection made";
    ?>

     

    ar papildus failu kurs norada $db_host, $db_user, $db_password

     

    Sini gadijuma neuzrada pilniba neko! KO es varetu but aizmirsis nokonfiguret? Vai varbut ko nepareizu izdarijis!

  13. Nekad nesu lietojis JS! Esmu php iesacejs! Sit mani nost bet es nesaprotu!

     

    <form action="index.php" method="post">
    <table width="390" border="0" height="10" align=center background="/style/add_style_green.png">
    <tr>
    <td>
    <!-- attiecigas bildes -->
    <img src="/style/bloods.png" />
    <img src="/style/blood.png"/>
    <img src="/style/underline.png" />
    <img src="/style/strip.png" />
    <img src="/style/gas_strip_os_83.png" />
    <img src="/style/link.png" />
    <img src="/style/img.png" />
    <img src="/style/gas_strip_os_83.png" />
    
    
    
    <a href="" border="0"><img src="/style/info68.png" border="0" /></a>
    <!-- attiecigas bildes END -->
    </td>
    </tr>
    </table>
    <table align=center width=396 border="0">
    <tr>
    <td>Niks:<font color="red">*</font> <input type="input" name="vards" size="15" style="background-color:#FBFBFB"></td>
    </tr>
    <tr>
    <td colspan=2>Komentars:<font color="red">*</font><br><textarea rows=4 cols=45 name="teksts" style="background-color:#FBFBFB"></textarea></td>
    </tr>
    <tr>
    <td><input type=submit value="Pievienot" name="aiziet">
     <input type=hidden value="<?php echo $_SERVER['REMOTE_ADDR']; ?>" name="aipii">
     <input type=hidden value="<?php echo time() ?>" name="laiks"></td>
    </tr>
    </form>
    </table>

    Neizdodas panakt velamo efektu, tapec palugsu lai Jus palabojat manu source!

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