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Darkangel

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Posts posted by Darkangel

  1. Es vnk velejos ustaisit taka admina paneli kura neviens ieksa netiek iznemot mani un lai nebutu jaraksta nekads login un parole + man ira mdsl un man ip mainas taka es gribeju atrast labaku veidu ka autorizeties. Jo man velak tas vis japarliek uz citu serveri busss. Un tape cereju ustaisit autorizaciju pec pc varda.

  2. <?php
    include "connect.php";
    
    
    // get data that sent from form
    $date = date("d-m-y---H-i");
    $ip = getenv("REMOTE_ADDR");
    $host = gethostbyaddr($ip);
    
    
    $sql="INSERT INTO ip(Datum, IP, Host)VALUES('$date', '$ip', '$host')";
    $result=mysql_query($sql);
    
    mysql_close();
    ?>

     

    Es netieku skaidriba kape vins nerada citu user pc vardu bet tikai to kuru uz ka stav pats web servers.

  3. Tu man radiji sita .

     

    /cs/Daily/DailyPic/photos/2007-01-10.jpg

    Varbūt vajag:

    cs/Daily/DailyPic/photos/2007-01-10.jpg

     

    A tu nevareji paradit paraugu ka vaig iskatities un man tas default imege gaja /cs/Daily/DailyPic/photos ar sitadu bet negaja dienas bilde pati

    un tiklidz es nomainiju no sita /cs/Daily/DailyPic/photos/ uz sadu cs/Daily/DailyPic/photos/ man nestradaja dienas bilde un default bilde ari vairs negaja

  4. Un es atradu vainu kape negaja kluda man bija seit

     

    $image_url = "http://darkangel.carnikava.com/cs/Daily/DailyPic/photos";
    
    $image_dir = "/cs/Daily/DailyPic/photos";
    
    $thumb_url = "http://darkangel.carnikava.com/cs/Daily/DailyPic/photos/thumbs";
    
    $thumb_dir = "/cs/Daily/DailyPic/photos/thumbs";
    
    $default = "/cs/Daily/DailyPic/photos/default.jpg";

     

    a vaidzeja but sadi

     

    $image_url = "http://darkangel.carnikava.com/cs/Daily/DailyPic/photos";
    
    $image_dir = "photos";
    
    $thumb_url = "http://darkangel.carnikava.com/cs/Daily/DailyPic/photos/thumbs";
    
    $thumb_dir = "photos/thumbs";
    
    $default = "photos/default.jpg";

  5. Man ira problema visu esu izdarijis ka vaig bet kad atveru vala lapu vins rada default bildi nevis tas dienas bildi kaut man vina ira pareizaja folderi

     

     

    <?
    
    $date = date("Y-m-d");
    
    $image_url = "http://darkangel.carnikava.com/cs/Daily/DailyPic/photos";
    
    $image_dir = "/cs/Daily/DailyPic/photos";
    
    $thumb_url = "http://darkangel.carnikava.com/cs/Daily/DailyPic/photos/thumbs";
    
    $thumb_dir = "/cs/Daily/DailyPic/photos/thumbs";
    
    $default = "/cs/Daily/DailyPic/photos/default.jpg";
    
    $ext = ".jpg";
    
    $photo = "$image_dir/$date" . $ext . "";
    
    
    
    if (file_exists ($photo)){
    
     		echo "
    		<div align=center>
    		<a href='$image_url/$date" . $ext . "' target='_blank'><img src='$thumb_url/$date" . $ext . "' border=0></a>
    		</div>
    	";
    
    } else {
    
     		echo "
    		<div align=center>
    		<img src='$default' border=0>
    		</div>
    	";
    }
    
    
    
    
    ?>

  6. Kads man var palidzet ar so scriptu es jau mokos vienu laiku un netieku skaidriba

    es gribu lai vins no datu bazes nolasa avatar nosaukumu piem devil.jpg

    un parada vinu mana profila

     

     

    <?php
    require_once('auth.php');
    ?>
    	<center>
    
    	<?php
    	$id = $auth->userid;
    	$username = $auth->username;
    	require("connect.php");
    	$sql = "SELECT * FROM user WHERE avatar = '$id'";
    	$res = mysql_query($sql);
    	$row = mysql_fetch_array($res);
    	echo '<img border="0" src="avatar/$row["avatar"]" width="100" height="100"><br>';
    	echo "User logged:".$username."<br>";
    	echo "Userid:".$id."<br>";
    	?>
    
    	</center>

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