Jump to content
php.lv forumi

Gizmo

Reģistrētie lietotāji
 View Profile  See their activity

  • Posts

    76

  • Joined

  • Last visited

 Content Type 

Posts posted by Gizmo

  1. Kā lai dabū infromāciju iekšā formā?

    in PHP skripti

    Posted

    Nu kaa:

    1. Klients nokachaa *.doc

    2. Ar wordu atver, palabo.

    3. Upload

    4. Lapaa include(*.doc)

    5. Un rezultaataa viss arii normaali paraadaas.

     

    Aaa, tikko paarbaudot izraadiijaas - paraadiijaas pareizi tapee ka tas tomeer ir *.htm formaataa, tikai extension nomainiits lai klientam ar wordu vinsh atvertos, bet kad klients to ir izlabojis un saglabaajis (vienalga kaadaa formaataa) - viss raadaas kaa vaig! Znachit nesanaaks jaunu *.doc includot, bet shitaa bishki apstraadaajot viss O.K.

  4. Kā lai dabū infromāciju iekšā formā?

    in PHP skripti

    Posted · Edited by Gizmo

    Par to ka es uztaisiiju ka lapas admins var nokachaat *.doc failu => editeet un tad upload atpakalj. Tur vinsh lapaa uzreiz tiek vienkaarshi izsaukts ar include()

    Itkaa diivaini taa, parasti jau includo *.inc vai *.php

    Uz man kompja viss notiek pareizi, bet tomeer var buut kaadi defekti uz citiem kompjiem, piemeeram, kuriem nau words vai kautkaa tml..

    Tas ir word dokuments!!

  9. failu ielade uz serveri

    in PHP skripti

    Posted

    Kā atrisināt problēmu: kā admins ieliku folderī /images/ bildi un ir viss O.K. bet kad tajā pašā folderī uploadoju ar formu to failu tad: 

    You don't have permission to access /images/050720014124_756.jpg on this server.

    Pats scripts:

    $uploaddir = 'bildes/';
$uploadfile = $uploaddir . basename($_FILES['userfile']['name']);

  12. PHP+MySQL=>print

    in PHP skripti

    Posted

    Kā lai dobon to ka bildes paklaujas manis definētajiem <td> izmēriem un katra attieciigi samazinaas vai palielinaas attieciibaa pret oriģinālu?

     

    printf("
<table class=table2 align=center bgcolor=black height=200 width=150 border=0>
<tr><td bgcolor=white width=150 height=150 align=center>
<img align=center src=\"visi/%s.jpg\">
</td></tr>
<tr><td bgcolor=gray height=50><font size=1>%s</font>
</td></tr></table>",$row["nosaukums"],$row["nosaukums"]);

  14. sesijas

    in PHP skripti

    Posted 

    <?php 
session_start(); 
header("Cache-control: private");
  $name = $_POST['name']; 
  $_SESSION['name'] = $name; 
?> 
Welcome to my website <strong><? echo $_SESSION['name']; ?></strong>!<br /> 
Let's see what happens on the <a href="page3.php">next page.</a><br /><br />

    Kapeec pirmajam kodam man apakšā izdrukā $name, bet naakamajaa nee?

    <?php 
session_start(); 
header("Cache-control: private");
?> 
Hey <strong><? echo $_SESSION['name']; ?></strong> Everything is still working!<br /><br />

  18. failu ielade uz serveri

    in PHP skripti

    Posted

    Sorry, kautkas nesanāk, kur lai iisti ievieto to chmod? Un ko apziimee 'fails' ?

    Tas tak nau jaaliek jau formaa?

    <?php
include ("conn.php");
$uploaddir = 'uploads/';
$uploadfile = $uploaddir . basename($_FILES['userfile']['name']);
print "<pre>";
if (move_uploaded_file($_FILES['userfile']['tmp_name'], $uploadfile)) {

$basename = ($_FILES['userfile']['name']);
$bilde = $basename;


if (empty($cena)) {
print ("Nesaņēmu cenu!<br>");
}
elseif (empty($izmers)) {
print ("Nesaņēmu izmēru!<br>");
}

else {
$result = @mysql_query("insert into gleznas values(null,'$bilde','$cena','$izmers')");
@mysql_free_result('$result');
echo "<script language=\"javascript\">location='m.php'</script>";
}
} else {
  print "Kautkas nesanāca:\n";
  print_r($_FILES);
}
print "</pre>";

?>

  22. failu ielade uz serveri

    in PHP skripti

    Posted · Edited by Gizmo 

    <?php
include ("conn.php");
$uploaddir = 'uploads/';
$uploadfile = $uploaddir . basename($_FILES['userfile']['name']);

print "<pre>";
if (move_uploaded_file($_FILES['userfile']['tmp_name'], $uploadfile)) {

$basename = ($_FILES['userfile']['name']);
$bilde = $basename;


if (empty($cena)) {
print ("Nesaņēmu cenu!<br>");
}
elseif (empty($izmers)) {
print ("Nesaņēmu izmēru!<br>");
}

else {
$result = @mysql_query("insert into gleznas values(null,'$bilde','$cena','$izmers')");
@mysql_free_result('$result');
echo "<script language=\"javascript\">location='m.php'</script>";
}
} else {
print "Kautkas nesanāca:\n";
print_r($_FILES);
}
print "</pre>";

?>

     

    Uz localhost viss bija O.K., bet uz servera izdrukaa:

     

    Warning: move_uploaded_file(uploads/IMGP1202.jpg): failed to open stream: Permission denied in /home/hosting/interjers/upload2.php on line 7

Warning: move_uploaded_file(): Unable to move '/tmp/phpKe49em' to 'uploads/IMGP1202.jpg' in /home/hosting/interjers/upload2.php on line 7
Kautkas nesanāca:
Array
(
[userfile] => Array
(
[name] => IMGP1202.jpg
[type] => image/pjpeg
[tmp_name] => /tmp/phpKe49em
[error] => 0
[size] => 77526
)

)

    Kas pa vainu?

  23. nelaist kur nevajag

    in PHP skripti

    Posted

    kāds būtu vispareizākais veids neļaut useram tikt pie citām lapām, kuras es negribu raadiit kjipa:

    login.php => ja viss ok laizju uz dati.php?usrid=$id , ja nee tad paliec turpat login.php

    A kaa lai izdara ka vinsh uzreiz neavar lietot dati.php?usrid=666

    itkaa ar cookies vareetu, bet tas arii nau droši.

×
×
  • Create New...